Answer:
I am an Aquarian and my least favourite zodiac is Leo...
Answer:
C. It's the ringmasters job to hold the show together. if something hour goes wrong they try there best to stall for time.
The answer is most likely A)
Interesting
the question please?
The easiest way to find such limits, where there is a numerator and a denominator is to apply <span><span>Hospital's Rule.
1st find the derivative of the numerator and the derivative of the denominator, if it still gives an indeterminate value, find the second derivative of N and D
3) lim sin(2x)/x when x →0
Derivative sin2x → 2cos2x
Derivative x→ 1
2cos2x/1 when x→0 , 2cos2x → 2
and lim sin(2x)/x when x →0 is 2
4) lim(sinx)/(2x²-x)
→cosx/(2x-1) when x →0 cosx/(2x-1) = -1
and lim(sinx)/(2x²-x) when x →0 is -1
and so on and so forth. Try to continue following the same principle
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