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2 years ago

Solve for x X^2 =16

Mathematics

2 answers:

NARA [144]2 years ago

7 0

Answer:

Step-by-step explanation:

X^2=16

4x4=16

Marina CMI [18]2 years ago

6 0

Answer:

Step-by-step explanation:

X=4

4×4=16

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What is 5m2- 15m- 200

vitfil [10]

Answer:

5(m + 5) (m - 8)

Step-by-step explanation:

5m2- 15m- 200

Start by pulling 5 out.

5(m^2 - 3m - 40)

We consider all factors of 40

1 40

2 20

4 10

5 8

Based on the middle term we know that 5 and 8 are our best option.

5(m 5) (m 8)

We know the signs have to be one + and one - because a - * - = + and + * + = +

Since 5 - 8 would give us -3 we know that our answer is

5(m + 5) (m - 8)

3 0

3 years ago

PLS HELP! (THE QUESTION IS A PICTURE CLICK ON THE QUESTION FIRST)

allsm [11]

All triangles angles in the inside add up to 180, so 180-76-72=32

8 0

2 years ago

The bible predicted many things about: answers: man's sin, God the Father, Christ.

Anettt [7]

Answer:

of what's right and wrong

Step-by-step explanation:

if you don't follow the Bible, when your a Christian, some say you go to the underworld

7 0

3 years ago

Find the average value of f(x+y)=sin(x+y) over

Troyanec [42]

For each given region $D$ , the average value of $f$ over $D$ is the integral of $f$ over $D$ divided by the area of $D$ . In both cases, $D$ is a rectangle so the area is trivial.

a. The area of $D$ is $\dfrac\pi3\cdot\dfrac{5\pi}3=\dfrac{5\pi^2}9$ . The integral of $f$ over $D$ is

$\displaystyle\int_0^{5\pi/3}\int_0^{\pi/3}\sin(x+y)\,\mathrm dx\,\mathrm dy$

$\displaystyle=\int_0^{5\pi/3}\left(\cos y-\cos\left(y+\dfrac\pi3\right)\right)\,\mathrm dy$

$=\sin\dfrac{5\pi}3-\sin\left(\dfrac{5\pi}3+\dfrac\pi3\right) - \sin0+\sin\dfrac\pi3=0$

So the average value of $f$ over this region is 0.

b. The area of $D$ is $\dfrac{2\pi}3\cdot\dfrac{7\pi}6=\dfrac{7\pi^2}9$ . The integral of $f$ is

$\displaystyle\int_0^{7\pi/6}\int_0^{2\pi/3}\sin(x+y)\,\mathrm dx\,\mathrm dy$

$=\displaystyle\int_0^{7\pi/6}\left(\cos y-\cos\left(y+\frac{2\pi}3\right)\right)\,\mathrm dy$

$=\sin\dfrac{7\pi}6-\sin\left(\dfrac{7\pi}6+\dfrac{2\pi}3\right) - \sin0+\sin\dfrac{2\pi}3=\dfrac{\sqrt3}2$

The average vale of $f$ over this region is then $\dfrac{\frac{\sqrt3}2}{\frac{7\pi^2}9}=\dfrac{9\sqrt3}{14\pi^2}$ .

4 0

2 years ago

Here is a rectangle abcd. the length of the rectangle is increased by 10%. the width of the rectangle is increased by 5%. find t

goblinko [34]

Answer:

Step-by-step explanation:

You have to find 5% of 20 and then add that onto 20

Then you need to find 10% of 30 and add that onto 30

Then add up all the sides because that is how you find perimeter.

HOPE THIS HELPS!!

5 0

2 years ago