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Artemon [7]
2 years ago
6

I need help please.............

Mathematics
1 answer:
UkoKoshka [18]2 years ago
3 0

Answer:

A: 4

B: it means that they have an absolute value of 4 levels between them.

C: 3+4

D: It will be greater than the value of a because you are adding onto it. If a is negative and b is positive thne it will be less than since you are subtracting a positive from a negative number

Step-by-step explanation:

Let me know if you need more in-depth on HOW to do it.

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Suppose 15 of the people who voted for dee had not voted at all. How would this change affect the ratio of gene's votes to total
Snezhnost [94]

Gene's votes to Total votes

= Gene's votes: Total votes - 15


Since you did not provide the number of votes, I will give an example.

55 people voted for Dee, 45 people voted for Gene.  This means the Total votes cast was 100.

The ratio of Dee's votes to total votes is: 55:100  ⇒  11:20 <em>when reduced</em>

The ratio of Gene's votes to total votes is: 45:100  ⇒  9:20 <em>when reduced</em>

If 15 people who voted for Dee did not vote, then the total number of voters is 85 so the ratios change as follows:

Dee: (55-15):(100-15)   ⇒   40:85   ⇒   8:17 <em>when reduced</em>

Gene: (45-0):(100-15)   ⇒   45:85  ⇒   9:17 <em>when reduced</em>


8 0
2 years ago
HELP ASAP PLZ i need help !<br>help me :((
kodGreya [7K]

Answer:

(1) g[f(x)]=\frac{8x-1}{12x-4}

(2)  g^{-1}(x)=\frac{x+1}{(3x-2)}

(3)    x=\frac{9+\sqrt{129} }{6},  \frac{9-\sqrt{129} }{6}

Step-by-step explanation:

Given functions f(x) = (4x-1)

are                     g(x)=\frac{2x+1}{3x-1}

(1)  g[f(x)]=\frac{2(4x-1)+1}{3(4x-1)-1}

                =\frac{8x-2+1}{12x-3-1}

                =\frac{8x-1}{12x-4}

(2) for g^{-1}(x), rewrite the function g(x) in terms of an equation

y=\frac{2x+1}{3x-1}

Substitute y in place of x and x in place of y, then solve for y.

x=\frac{2y+1}{3y-1}

(3y-1)x = 2y+1

3xy - x = 2y + 1

3xy - 2y = x + 1

y(3x-2) = x + 1

y=(\frac{x+1}{3x-2} )

⇒ g^{-1}(x)=\frac{x+1}{(3x-2)}

(3)    f[g(x)]=(x-1)

       f[g(x)]=4[\frac{2x+1}{3x-1}] =(x-1)

⇒    \frac{(8x+4)-(3x-1)}{3x-1}=(x-1)

⇒    \frac{8x-3x+4+1}{3x-1}=(x-1)

⇒    \frac{5x+5}{(3x-1)}=(x-1)

⇒    5x+5=(3x-1)(x-1)

⇒    5x+5=3x^2-3x-x+1

⇒   5x+5=3x^2-4x+1

⇒   3x^2-9x-4=0

⇒    x=\frac{9\pm\sqrt{(-9)^2-4(-4)\times3} }{2\times3}

   x=\frac{9\pm\sqrt{81+48} }{6}

   x=\frac{9\pm\sqrt{129} }{6}

   x=\frac{9+\sqrt{129} }{6},  \frac{9-\sqrt{129} }{6}

4 0
3 years ago
Emma ran 3.5 kilometers while grace ran 380 meters who ran further ???
miv72 [106K]
Emma because she ran 3500 meters. 3.5 *1000 = 3500 meters.
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Solve this system of linear equations. Separate
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Answer:

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Step-by-step explanation:

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Please help ASAP with these problems!
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Answer:

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