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Sindrei [870]
3 years ago
12

What's the answer to number 3

Mathematics
1 answer:
Evgesh-ka [11]3 years ago
3 0
Do you know what you need to do to solve this problem?
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How would you do this problem?
ddd [48]
First you would do the square root of two which is about 1.4. now you would do 10+1.4 which is 11.4. now you do 4 divided by 11.4 which is about 0.4
8 0
3 years ago
Read 2 more answers
You are carpeting a room in a house for your job. You have a boss that likes to play jokes, so instead of just giving you the di
forsale [732]

Answer:

x^2-4x+3

63\ \text{sq. units}

Step-by-step explanation:

l = Length = \dfrac{x^2-x-6}{x-5}

w = Width = \dfrac{x^2-6x+5}{x+2}

Area is given by

A=lw\\\Rightarrow A=\dfrac{x^2-x-6}{x-5}\times\dfrac{x^2-6x+5}{x+2}\\\Rightarrow A=\dfrac{x^2-3x+2x-6}{x-5}\times\dfrac{x^2-5x-1x+5}{x+2}\\\Rightarrow A=\dfrac{(x-3)(x+2)}{x-5}\times\dfrac{(x-5)(x-1)}{x+2}\\\Rightarrow A=(x-3)(x-1)\\\Rightarrow A=x^2-4x+3

Area of the room is x^2-4x+3.

If x=10

Area of the room

A=x^2-4x+3=10^2-4\times 10+3\\\Rightarrow A=63\ \text{sq. units}

So, the amount of carpet needed would be 63\ \text{sq. units}.

4 0
3 years ago
How do you reduce fractions?
SIZIF [17.4K]
Find a number to will divide into both the numerator and denominator equally.

For example, take a look at this fraction: 10/15

What number can both divide evenly into the numerator and denominator? Well, 5!

10/15 / 5/5 = 2/3


3 0
3 years ago
QUICK! I NEED HELP ASAP
Zolol [24]

Answer:

w=6

Step-by-step explanation:  you should just look it up on line

5 0
3 years ago
Read 2 more answers
A) laplace transform of 4t^2 sin 3t + e^-2t + t<br> b)......................... te^-2t cos 3t
Sonbull [250]

Answer:

a.L(s)=(-24)\frac{81-s^4}{(s^2+9)^4}+\frac{1}{s+2}+\frac{1}{s+1}

b.L(s)=-\frac{-s^2-4s+5}{(s^2+4s+13)^2}

Step-by-step explanation:

We have to find the laplace transform of each function

a.4t^2sin3t+e^{-2t}+t

L(t^nf(t))=(-1)^n\frac{d^nF(s)}{ds^n}

L(t^n)=\frac{n!}{s^n+1}

L(e^{at})=\frac{1}{s-a}

L(sinat)=\frac{a}{s^2+a^2}

L(e^{at}cosbt)=\frac{s-a}{(s-a)^2+b^2}

Apply the formula

Then we get

12(-1)^2\frac{d^2(\frac{1}{s^2+9})}{ds^2}+\frac{1}{s+2}+\frac{1}{s+1}

(-24)\frac{s^4+81+18s^2-2s^4-18s^2}{(s^2+9)^4}+\frac{1}{s+2}+\frac{1}{s+1}

L(s)=(-24)\frac{81-s^4}{(s^2+9)^4}+\frac{1}{s+2}+\frac{1}{s+1}

b.te^{-2t}cos3t

f(t)=e^{-2t}cos3t

F(s)=\frac{s+2}{(s+2)^2+9}=\frac{s+2}{s^2+4s+13}

L(s)=-\frac{dF(s)}{ds}=-\frac{s^2+4s+13-(2s+4)(s+2)}{(s^2+4s+13)^2}

L(s)=-\frac{5-s^2-4s}{(s^2+4s+13)^2}

5 0
3 years ago
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