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Andreyy89
3 years ago
9

Determine the mass of KNO3 that dissolves in 100. grams of water at 40 degrees celsius to produce a saturated solution

Chemistry
1 answer:
77julia77 [94]3 years ago
4 0
This is the reference data.
100 g H₂O, 40°C
c=63,9 g/100 g w.
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Calculate the change in pH for each buffer upon the addition of 1.0 mL of 1.00MHCl. Express your answers using two decimal place
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1.9 mL. en r t tu y y y
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C) What volume of dilute HNO3 solution (0.150 mol/L) would be required
babymother [125]

Answer: 1.15L

Explanation:Please see attachment for explanation

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3 years ago
What are rarefactions and compressions of sound waves?
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6 0
3 years ago
Calcium carbide reacts with water to produce acetylene gas according to the following equation: CaC2(s) + 2H2O(l)C2H2(g) + Ca(OH
mars1129 [50]

Answer : The number of moles of CaC_2 reacted was, 0.214 moles.

Explanation :

First we have to calculate the mole of C_2H_2 gas.

Using ideal gas equation:

PV=nRT

where,

P = Pressure of C_2H_2 gas = 748 mmHg - 23.8 mHg = 724.2 mmHg = 0.953 atm   (1 atm = 760 mmHg)

V = Volume of C_2H_2 gas = 5.50 L

n = number of moles C_2H_2 = ?

R = Gas constant = 0.0821L.atm/mol.K

T = Temperature of C_2H_2 gas = 25^oC=273+25=298K

Putting values in above equation, we get:

0.953atm\times 5.50L=n\times (0.0821L.atm/mol.K)\times 298K

n=0.214mol

Now we have to calculate the moles of CaC_2

The balanced chemical reaction is:

CaC_2(s)+2H_2O(l)\rightarrow C_2H_2(g)+Ca(OH)_2(aq)

From the balanced chemical reaction we conclude that,

As, 1 mole of C_2H_2 gas produced from 1 mole of CaC_2

So, 0.214 mole of C_2H_2 gas produced from 0.214 mole of CaC_2

Therefore, the number of moles of CaC_2 reacted was, 0.214 moles.

4 0
3 years ago
What is the rate constant of a first-order reaction that takes 143 seconds for the reactant concentration to drop to half of its
algol [13]

Answer:

k = 4.85 x 10⁻³ / s

Explanation:

For a first order reaction we have two very important equations we need to memorize:

ln ( N/N₀ ) = -kt

and,

0.693/ k = t₁/₂

where k is the rate constant and t i is the halflife which can be derived from the first equation.

0.693/ k = t₁/₂   ⇒  k = 0.693 / t₁/₂  

k = 0.693 / 143 s = 4.85 x 10⁻³ / s

3 0
3 years ago
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