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timurjin [86]
3 years ago
7

Which of the following elements has the greatest metallic character? Rb Mo Au B

Chemistry
2 answers:
max2010maxim [7]3 years ago
8 0

Answer:

Rb

Explanation:

jek_recluse [69]3 years ago
5 0

Answer:

Au. fifififiof

Explanation:

djdjdjndsksidndndnendnnd

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During the Big Bang, what were the two main chemical elements created?
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During the big band only the lightest elements were formed – hydrogen<span> and </span>helium<span> along with trace amounts of </span>lithium<span> and </span>beryllium<span>.</span>
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3 years ago
Read 2 more answers
An ideal gas originally at 0.85 atm and 66°C was allowed to expand until its final volume, pressure, and temperature were 94 mL,
svet-max [94.6K]

Answer : The initial volume was, 71.2 mL

Explanation :

To calculate the volume when temperature and pressure has changed, we use the equation given by combined gas law.

The equation follows:

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1,V_1\text{ and }T_1 are the initial pressure, volume and temperature of the gas

P_2,V_2\text{ and }T_2 are the final pressure, volume and temperature of the gas

We are given:

P_1=0.85atm\\V_1=?\\T_1=66^oC=[66+273]K=339K\\P_2=0.60atm\\V_2=94mL\\T_2=43^oC=[43+273]K=316K

Now put all the given values in above equation, we get:

\frac{0.85atm\times V_1}{339K}=\frac{0.60atm\times 94mL}{316K}

V_1=71.2mL

Therefore, the initial volume was, 71.2 mL

4 0
3 years ago
What coefficient is needed to balance the reaction
tensa zangetsu [6.8K]

Answer:

OD. 2HCl

Explanation:

A balanced equation needs the equal # of each element on BOTH sides.

By putting a 2 in front of HCl you now have 2 hydrogens on both sides and 2 chlorines. The Ca and CO3 are already balanced.

5 0
2 years ago
What is the term for the amount of energy that is needed for a chemical reaction to occur?
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3 years ago
Calculate the amount in grams of Na2CO3 needed in a reaction with HCl to produce 120g NaCl?
klemol [59]
The balanced chemical reaction is written as :

Na2CO3<span> + 2HCl === 2NaCl + H2O + CO2
</span>
We are given the amount of NaCl to be produced from the reaction. This will be the starting point for the calculations. We do as follows:

120 g NaCl ( 1 mol / 58.44 g) ( 1 mol Na2CO3 / 2 mol NaCl)( 105.99 g / 1 mol ) = 1108.82 g Na2CO3 needed
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