3 years ago

86 times 25 standard algorythm

Mathematics

1 answer:

bija089 [108]3 years ago

5 0

86 multiplied by twenty five is two thousand one hundred fifty

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4 years ago

How do I go about solving (27x^3/8y^9)^5/3? And what is the role of the numerator and denominator?

MrRissso [65]

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Now, If the exponent was negative like you asked....

$\left( \frac{27x^3}{8y^9}\right)^ {-\frac{5}{3}} \\\\\\ =\left( \frac{8y^9}{27x^3}\right)^ {\frac{5}{3}}\\\\\\ =\left( \frac{(2y^3)^3}{(3x)^3}\right)^ \frac{5}{3} \\\\\\ = \frac{(2y^3)^{3 \times \frac{5}{3} }}{(3x)^{3 \times \frac{5}{3} }} \\\\\\ =\frac{(2y^3)^{5 }}{(3x)^5} \\\\\\ =\frac{32y^{15}}{243x^5}$

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3 years ago

Ana is retiring next year from the school that she has taught at for the last 25 years. Her pension pays a monthly salary of $1,

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<span>Your answer would be $2,024.02.</span>

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3 years ago

Read 2 more answers

Select all of the equations that have the same solution as the equation -9(x-18)=108

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The letter A !!!!! has the solution x=6 that it the same solution

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