The probabability of winning on at least 1 bet is equal to 1 less the probaility of not winning on either of the 6 bets.
The probability of not wining on any bet is independent of winning or not winning on any of the bets, so the combined probability is calculated as the product of each individual probability.
Each indivitual probability of not winning the is:
(number of not winning outcomes) / (number of possible outcomes) = 37 / 38.
Then, the combined probability of not winning the six times is: (1/38)*(37/38)*(37/38)*(37/38)*(37/38)*(37/38) =(37/38)^6
Therefore, the probability of winning at least one bet is:
= 1 - (37/38)^6 ≈ 1 - 0.973684 ≈ 0.03.
Answer: 0.03.
Answer:
b = 1
Step-by-step explanation:
8 = b - 1 + 8b
<em>combine like terms</em>
8 = 9b - 1
<em>add 1 to both sides of the equation</em>
<em>8 + 1 = 9b - 1 + 1</em>
<em>8 + 1 = 9b</em>
9 = 9b
<em>divide both sides of the equation by 9</em>
9/9 = 9b/9
1 = b
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Answer:$35
Step-by-step explanation:well each cookie cost $3.50 so for $14 there are only 4 cookies so for ten it will cost $35 cause 14+14=28 and you need to 2 more cookies so you will add 2 more which is $7 and $7+$28=$35.Hope I’m right
Answer:
6^-4 ÷ 3^-4
6^-4/3^-4
Since their powers are negative
Flip them both so the negative index is lost.
It now becomes
3^4/6^4
81/1296
=1/16
Y =2x +14
-4x –y = 4 so y = -4x – 4
2x + 14 = -4x – 4
2x + 4x = -4 - 14
6x = -18
x = -18/6
x = -3
Y =2x +14
y = 2(-3) +14
y= -6 +14
y=8
answer:
y-coordinate is 8