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BlackZzzverrR [31]
3 years ago
8

Simplify (4ab^2)^3 Any help is appreciated

Mathematics
1 answer:
Pie3 years ago
3 0

Answer:

64a^{3} b^{6}

Step-by-step explanation:

1) Distribute the exponent outside of the parentheses to the terms inside the parentheses. In this case, multiply the 3 outside the parentheses with the exponent of each of the terms inside:

(4ab^{2} )^3

4^{3} · a^{3} · b^{6}

2) The variables are fine - you can't simplify them further. All you need to do now is multiply the 4^{3} out. Remember that it's kind of like asking, "what is 4 × 4 ×4?"

4 · 4 · 4 · a^{3} · b^{6}

16 · 4 · a^{3} · b^{6}

64a^{3} b^{6}

Therefore, 64a^{3} b^{6} is the answer.

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Answer it pls and explain too​
snow_tiger [21]

Answer:

  y-intercept: (0, 5); slope: 1/4

Step-by-step explanation:

The slope (m) is found from ...

  m = (y2 -y1)/(x2 -x1)

Using the first two points in the table, this is ...

  m = (8 -6)/(12 -4) = 2/8 = 1/4 . . . . . eliminates choices A and C

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Then, the point-slope form of the equation of the line can be written as ...

  y -y1 = m(x -x1)

  y -6 = (1/4)(x -4) . . . fill in known values

  y = 1/4x -1 +6 . . . . . add 6

  y = 1/4x +5

Then the value of y when x=0 is ...

  y = 0 +5 = 5

So, the y-intercept is (0, 5) and the slope is 1/4, matching the last choice.

7 0
3 years ago
For the function defined by f(t)=2-t, 0≤t<1, sketch 3 periods and find:
Oksi-84 [34.3K]
The half-range sine series is the expansion for f(t) with the assumption that f(t) is considered to be an odd function over its full range, -1. So for (a), you're essentially finding the full range expansion of the function

f(t)=\begin{cases}2-t&\text{for }0\le t

with period 2 so that f(t)=f(t+2n) for |t| and integers n.

Now, since f(t) is odd, there is no cosine series (you find the cosine series coefficients would vanish), leaving you with

f(t)=\displaystyle\sum_{n\ge1}b_n\sin\frac{n\pi t}L

where

b_n=\displaystyle\frac2L\int_0^Lf(t)\sin\frac{n\pi t}L\,\mathrm dt

In this case, L=1, so

b_n=\displaystyle2\int_0^1(2-t)\sin n\pi t\,\mathrm dt
b_n=\dfrac4{n\pi}-\dfrac{2\cos n\pi}{n\pi}-\dfrac{2\sin n\pi}{n^2\pi^2}
b_n=\dfrac{4-2(-1)^n}{n\pi}

The half-range sine series expansion for f(t) is then

f(t)\sim\displaystyle\sum_{n\ge1}\frac{4-2(-1)^n}{n\pi}\sin n\pi t

which can be further simplified by considering the even/odd cases of n, but there's no need for that here.

The half-range cosine series is computed similarly, this time assuming f(t) is even/symmetric across its full range. In other words, you are finding the full range series expansion for

f(t)=\begin{cases}2-t&\text{for }0\le t

Now the sine series expansion vanishes, leaving you with

f(t)\sim\dfrac{a_0}2+\displaystyle\sum_{n\ge1}a_n\cos\frac{n\pi t}L

where

a_n=\displaystyle\frac2L\int_0^Lf(t)\cos\frac{n\pi t}L\,\mathrm dt

for n\ge0. Again, L=1. You should find that

a_0=\displaystyle2\int_0^1(2-t)\,\mathrm dt=3

a_n=\displaystyle2\int_0^1(2-t)\cos n\pi t\,\mathrm dt
a_n=\dfrac2{n^2\pi^2}-\dfrac{2\cos n\pi}{n^2\pi^2}+\dfrac{2\sin n\pi}{n\pi}
a_n=\dfrac{2-2(-1)^n}{n^2\pi^2}

Here, splitting into even/odd cases actually reduces this further. Notice that when n is even, the expression above simplifies to

a_{n=2k}=\dfrac{2-2(-1)^{2k}}{(2k)^2\pi^2}=0

while for odd n, you have

a_{n=2k-1}=\dfrac{2-2(-1)^{2k-1}}{(2k-1)^2\pi^2}=\dfrac4{(2k-1)^2\pi^2}

So the half-range cosine series expansion would be

f(t)\sim\dfrac32+\displaystyle\sum_{n\ge1}a_n\cos n\pi t
f(t)\sim\dfrac32+\displaystyle\sum_{k\ge1}a_{2k-1}\cos(2k-1)\pi t
f(t)\sim\dfrac32+\displaystyle\sum_{k\ge1}\frac4{(2k-1)^2\pi^2}\cos(2k-1)\pi t

Attached are plots of the first few terms of each series overlaid onto plots of f(t). In the half-range sine series (right), I use n=10 terms, and in the half-range cosine series (left), I use k=2 or n=2(2)-1=3 terms. (It's a bit more difficult to distinguish f(t) from the latter because the cosine series converges so much faster.)

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Hello I need help with my homework if someone could help me and explain to me how this works that would be great thank you
Tatiana [17]

Answer:


Step-by-step explanation:

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7 0
3 years ago
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HELP ASAP!!! explanation requiredd!
Mkey [24]

(7x-5)+(3x-15)=180°

10x-20=180

10x=200

x=20

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3(20)-15 + E = 180

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E = 135°

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6 0
2 years ago
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Papessa [141]

Answer:

The bank charged 56 dollars in interest

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