Help with this question please answer choices are 35° 55° 125° 145°
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Using the slope line formula,
The slope of line y = mx is 1.0315.
We have given that,
parabola equation is y = 5x - 3x²
line passing through origin is in the form of y = mx
==> mx = 5x - 3x²
==> 3x²+ mx - 5x = 0
==> 3x² + x(m -5) = 0
==> x(3x + (m -5)) = 0
==> x = 0 , x = (5 -m)/3
The total area of the bounded region is then the integral of 5x - 3x² from x = 0 to x = (5-m)/3
Area under y = 5x - 3x2 and y = mx is (125/54)/2 = 125/108
==> [0 to (5 -m)/3] ∫(5x - 3x²-mx )dx = 125/108
==> [0 to (5 -m)/3]∫( (5 - m)x - 3x2 )dx = 125/108
==> [0 to (5 -m)/3] ((5 - m)x²/2 - x³ )= 125/108
==> (5 - m)[(5 -m)/3]²/2 - ((5 -m)/3)³ = 125/108
==> (5 -m)³/18 - (5 -m)³/27 = 125/108
==> (5 -m)³/54 = 125/108
==> (5 -m)³ = 125/2
==> (5 -m) = 3.9685
==> m = 5 - 3.9685
==> m = 1.0315
Hence slope of line = 1.0315
To learn more about slope of line , refer:
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