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Gennadij [26K]
4 years ago
12

A freight elevator is being loaded with identical 76-pound boxes. The elevator can carry no more than 2000 pounds. How many boxe

s can be loaded on the elevator.
Mathematics
2 answers:
guapka [62]4 years ago
7 0

Answer:

The maximum number of 76-pound boxes that can be loaded in the elevator is:

  • <u>26 boxes</u>.

Step-by-step explanation:

Since the maximum lift capacity is 2000 pounds and each box is identical (meaning there are no heavier or lighter boxes) than 76 pounds, the number of boxes can be identified by the following equation:

  • The maximum number of boxes = maximum lift capacity / weight per box.

Whereby replacing the values we get:

  • Maximum number of boxes = 2000 pounds / 76 pounds
  • <u>Maximum number of boxes = 26.3158 boxes</u>

Since the boxes are represented by integers, <u>the maximum number of boxes that can be loaded into the elevator at one time is 26</u>.

pishuonlain [190]4 years ago
4 0
Take 2000 divide 76 =26.3 so the elevator can carry 26 boxes
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2. The path of a high diver is given by y = + (2x2 – 9x – 56), where y is the height of the diver
timofeeve [1]

Answer:

The diver will be 8 feet from the end of the board when he hits the water.

Step-by-step explanation:

The diver hits the water when y = 0.

To find the distance, we have to find the values of x when y = 0.

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

ax^{2} + bx + c, a\neq0.

This polynomial has roots x_{1}, x_{2} such that ax^{2} + bx + c = (x - x_{1})*(x - x_{2}), given by the following formulas:

x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}

x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}

\bigtriangleup = b^{2} - 4ac

In this problem, we have that:

y = 2x^{2} - 9x - 56

2x^{2} - 9x - 56 = 0

So

a = 2, b = -9, c = -56

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It is a horizontal distance, so the answer is a positive value.

The diver will be 8 feet from the end of the board when he hits the water.

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