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pav-90 [236]
3 years ago
5

Write he ratio that compares $7 1/2 dollars to 3/4 pound of coffee dollars to pounds of coffee=

Mathematics
1 answer:
Anna35 [415]3 years ago
8 0
You would multiply both and then the answer you would put into ratio form
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if there are two containers of sugar solution, the first is 4% concentration and second is 8% concentration. how much of each sh
Elina [12.6K]

Answer:

<u>30 gallons solution 4% and 10 gallons solution 8%</u>

Step-by-step explanation:

<h3>x•4%+y•8%=40•5% </h3>

<em><u>4x+8y=40•5 and x+y=40</u></em>

x=40-y

4(40-y)+8y=200

160-4y+8y=200

4y=200-160

4y=40 => y=10 (gallons solution 8%)

=> x=40-10=30 (gallons solution 4%)

30 gallons solution 4% and 10 gallons solution 8%

5 0
2 years ago
Which equation would help you find the missing side length in the right triangle shown?
irina [24]
Equation a^2 + b^2 = c^2
c = longest side, unknown
The answer is D.
12^2 + 10^2 = c^2
7 0
2 years ago
Dustin has only nickels and quarters in his piggy bank. He has 49 coins total for a combined value of $8.85. How many of each ty
eduard
Well obviously quarters equal 25 cents.  So you have to divide the 8.85 by 25 first.  That means he could have 35 quarters.  That least the rest as being dimes.  So find the remaining amount of the 8.85.  If you have 35 quarters that's $8.75.  And 8.85 minus 8.75 is 10 cents.  which would be 2 nickels.  That only adds up 37 coins.  So you break down one of the 25.  That would mean 5 more coins could be nickels.  Add 37 and 5 to get 42.   Do it again.  25 cents in nickels would be 5 more coins.  would be 46.  that would be missing 2 coins. But don't forget you're also subtracting from the 35 quarters. Now you would technically have 12 nickels and 33 quarters.  So you can do it one more time.  32 quarters means there is $8 in quarters at this point.

Now add you have 12 nickels, and you made 5 more.  That's 17 nickels.  That equals 85 cents.  So add 17 and 32 to be sure you have 49 coins, which you do. 


So 17 nickels, 32 quarters to equal 49 coins and $8.85

(sorry some of it got mixed up above because I was forgetting to subtract the quarters from the total as I changed them to nickels, so pay attention to the end)
8 0
3 years ago
Determine whether there is a difference between the two data sets that is not apparent from a comparison of the measures of cent
Iteru [2.4K]

Answer:

It seems the question is incomplete as the two data sets implied from the question are not visible.

However, two data sets having identical measures of center have a difference.

Step-by-step explanation:

Let's consider these two data sets:

2, 2, 3, 5, 6, 6 and 1, 1, 1, 1, 1, 19

Both were contrived.

The most reliable among the measures of center is the mean. The mean of each is calculated by summing the data and dividing by the number of elements. In both sets, the mean is 4.

The data in the first set seem to be concentrated around the mean indeed. But for the second data set, one of them, 19, is obviously very far from the others and the mean. We need another measure to describe this: standard deviation.

Its formula is:

\rho=\sqrt{\dfrac{\sum (x-\overline{x})^2}{n}}

x represents each data, \overline{x} is the mean and n is the number of items. x-\overline{x} is the deviation from the mean of each data item.

For the first data set, \rho=\sqrt{6}=2.45

For the second data set,

\rho=\sqrt{45}=6.71

The low value of \rho for the first set indicates that the items are all closer to the mean than for the second set.

Variance is the square of the standard deviation. It could also be used.

7 0
3 years ago
What’s the students GPA?
andreyandreev [35.5K]

Answer:

The student's GPA is 2.8666.

Step-by-step explanation:

A grade is 4.0, B grade is 3.0, C grade is 2.0. For each credit, add the value of the letter grade. So:

Math, 2 credits, grade A: (4x2=8)

English, 5 credits, grade B: (5x3=15)

Physics, 4 credits, grade B: (4x3=12)

German, 4 credits, grade C: (4x2=8)

The numbers add up to 43, then divide by the number of credits (15) to get:

43/15=GPA of 2.8666.

6 0
3 years ago
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