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2 years ago

3. The point (12,9) is included in a direct variation. What is the constant of variation? (1 point)

Mathematics

2 answers:

vekshin12 years ago

8 0

c ok hope that's correct

Bogdan [553]2 years ago

3 0

Answer:

it is B, 3/4

Step-by-step explanation:

i just took it

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ILL GIVE A BRAINLIEST FOR THE ANSWER THAT HELPS ME THE MOSTT.

Nuetrik [128]

he would be born june 12 1962

4 0

2 years ago

Please help Complete the equation describing how x and y are related.

djverab [1.8K]

Answer:

y = 5x + 3

Step-by-step explanation:

The answer that belongs in the ? is 5.

4 0

1 year ago

The Sky Ranch is a supplier of aircraft parts. Included in stock are 6 altimeters that are correctly calibrated and two that are

almond37 [142]

Answer:

For x = 0, P(x = 0) = 0.35

For x = 1, P(x = 1) = 0.54

For x = 2, P(x = 2) = 0.11

For x = 3, P(x = 3) = 0

Step-by-step explanation:

We are given that the Sky Ranch is a supplier of aircraft parts. Included in stock are 6 altimeters that are correctly calibrated and two that are not. Three altimeters are randomly selected, one at a time, without replacement.

Let X = the number that are not correctly calibrated.

Number of altimeters that are correctly calibrated = 6

Number of altimeters that are not correctly calibrated = 2

Total number of altimeters = 6 + 2 = 8

(a) For x = 0: means there are 0 altimeters that are not correctly calibrated.

This means that all three selected altimeters are correctly calibrated.

Total number of ways of selecting 3 altimeters from a total of 8 = $^{8}C_3$

The number of ways of selecting 3 altimeters from a total of 6 altimeters that are correctly calibrated = $^{6}C_3$

So, the required probability = $\frac{^{6}C_3}{^{8}C_3}$

= $\frac{20}{56}$ = 0.35

(b) For x = 1: means there is 1 altimeter that is not correctly calibrated.

This means that from three selected altimeters; 1 is not correctly calibrated and 2 are correctly calibrated.

Total number of ways of selecting 3 altimeters from a total of 8 = $^{8}C_3$

The number of ways of selecting 2 correctly calibrated altimeters from a total of 6 altimeters that are correctly calibrated = $^{6}C_2$

The number of ways of selecting 1 not correctly calibrated altimeters from a total of 2 altimeters that are not correctly calibrated = $^{2}C_1$

So, the required probability = $\frac{^{6}C_2 \times ^{2}C_1 }{^{8}C_3}$

= $\frac{30}{56}$ = 0.54

(c) For x = 2: means there is 2 altimeter that is not correctly calibrated.

This means that from three selected altimeters; 2 are not correctly calibrated and 1 is correctly calibrated.

Total number of ways of selecting 3 altimeters from a total of 8 = $^{8}C_3$

The number of ways of selecting 1 correctly calibrated altimeters from a total of 6 altimeters that are correctly calibrated = $^{6}C_1$

The number of ways of selecting 2 not correctly calibrated altimeters from a total of 2 altimeters that are not correctly calibrated = $^{2}C_2$

So, the required probability = $\frac{^{6}C_1 \times ^{2}C_2 }{^{8}C_3}$

= $\frac{6}{56}$ = 0.11

(d) For x = 3: means there is 3 altimeter that is not correctly calibrated.

This case is not possible, so this probability is 0.

6 0

3 years ago

A street light is at the top of a 11 ft tall pole. A woman 6 ft tall walks away from the pole with a speed of 7 ft/sec along a s

zheka24 [161]

Answer:

The answer is 8.5 Ft/Sec.

The tip of the woman's shadow is moves from the base of the pole when she is 50ft away at the speed of 8.5 Ft/Sec

Step-by-step explanation:

The tip of the woman's shadow is moves from the base of the pole when she is 50ft away at the speed of 8.5 Ft/Sec

The solution and explanation is attached.

Download pdf

7 0

3 years ago

Please help need asap

larisa86 [58]

Answer to the nearest tenth is 20.8

4 0

1 year ago