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Assoli18 [71]
3 years ago
9

what is the equation of a line that is parallel to x - 2y = -4 and passes through the point (0, 0) ?​

Mathematics
1 answer:
vfiekz [6]3 years ago
8 0

Answer:

x - 2y = -4

x - 2y +4 = -4+4

x -2y +4= 0

x -2y +4 +2y= 0+2y

x+4 =2y

(x+4)/2 =2y/2

x/2 +2= y

slope of the line: 1/2    the point (0, 0)

                    (y-0)= (1/2)(x-0)

Answer:            y= (1/2)x

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To find the new divisor, subtract the product of the divisor and the quotient digit (2·15=30) and bring down the next digit of the original dividend. Now, you have a dividend of 147 and a divisor of 15. Repeat the process as above.

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5 0
3 years ago
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gavmur [86]

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4 0
3 years ago
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aivan3 [116]

Answer:

Step-by-step explanation:

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Yuliya22 [10]

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B

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Hope this helped!

6 0
3 years ago
Read 2 more answers
What is the product of 1 2/3 and −3 1/2?
Fynjy0 [20]
<span>1 2/3 x  −3 1/2
= 5/3 x -7/2
= - 35/6
= - 5 5/6

answer
A. </span><span>−5 5/6 ​</span>
6 0
3 years ago
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