8+2(1+12÷2)^2 Please explain
1 answer:
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Answer:
Step-by-step explanation:
Absolute Value Inequality entered :
|y+2|>6
Step by step solution :
Step 1: Rearrange this Absolute Value Inequality
Absolute value inequalitiy entered
|y+2| > 6
Step 2: Clear the Absolute Value Bars
Clear the absolute-value bars by splitting the equation into its two cases, one for the Positive case and the other for the Negative case.
The Absolute Value term is |y+2|
For the Negative case we'll use -(y+2)
For the Positive case we'll use (y+2)
Step 3: Solve the Negative Case
-(y+2) > 6
Multiply
-y-2 > 6
Rearrange and Add up
-y > 8
Multiply both sides by (-1)
Remember to flip the inequality sign
y < -8
Which is the solution for the Negative Case
Step 4: Solve the Positive Case
(y+2) > 6
Rearrange and Add up
y > 4
Which is the solution for the Positive Case
Step 5:
Wrap up the solution
y < -8
y > 4
Solutions in Interval Notation
(-∞,-8)
(4,+∞)
Solutions on the Number Line
Two solutions were found :
y > 4
y < -8
