Answer:
a) 
b) 
And replacing we got:

c) 


And adding we got:

Step-by-step explanation:
Previous concepts
The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".
Solution to the problem
Let X the random variable of interest, on this case we now that:
The probability mass function for the Binomial distribution is given as:
Where (nCx) means combinatory and it's given by this formula:
Assuming the following questions:
a. exactly five
For this case we can use the probability mass function and we got:

b. at least one
For this case we want this probability:

And we can use the complement rule and we got:


And replacing we got:

c. between four and six, inclusive.
For this case we want this probability:




And adding we got:

The answer is (-7r-6s)/3s
Answer:
D
Step-by-step explanation:
whenever you see this ^ you now it's not linear equation
Answer:
The system of inequalities that represents this situation is:
x+y≥10
6x+4y≤50
Step-by-step explanation:
As the statement says that Laura wants to provide one party favor per person to at least 10 guests, the first inequality would indicate that the number of stuffed animals plus the number of toy trucks should be equal or greater than 10:
x+y≥10
Also, the statement indicates that miniature stuffed animals cost $6.00 each and the toy trucks cost $4.00 each and that Laura has $50. From this, you would have an inequality that indicates that 6 for the number of miniature stuffed animals and 4 for the number of toy trucks would be equal or less than 50:
6x+4y≤50
The answer is that the system of inequalities that represents this situation is:
x+y≥10
6x+4y≤50