In a series of columns, or groups, and rows, or periods.
Answer : The energy change for the reaction is CsCl is, 95 KJ/mole
Explanation :
The steps involved in the formation of :
(1) Conversion of gaseous potassium atoms into gaseous potassium ions.
= ionization energy of potassium = 419 kJ/mol
(2) Conversion of gaseous bromine atoms into gaseous bromine ions.
= electron affinity energy of bromine = -324 kJ/mol
The overall reaction will be:
To calculate the overall energy change the expression used is:
Now put all the given values in this equation, we get:
Therefore, the energy change for the reaction is CsCl is, 95 KJ/mole
Answer:
Explanation:
The solution of known concentration is expressed as molarity. Molarity is the mole fraction of solute (i.e. the dissolved substance) per liter of the solution, Molarity is also commonly called molar concentration.
Mathematically;
To copy and complete the road map from the given question, we have the following array:
Volume A (L)
↓
d. multiplied by the molarity of A
↓
moles A
↓
b. multiplied by the moles of B / moles of A
↓
moles B
↓
c. divided by the molarity of B
↓
volume B (L)
B because acetic acid is a weak acid and large quantity means you make it become concentrated
Zinc is a Transition Metal. You can only know how many valence electrons Zinc loses by the valence electrons of Phosphorous. Because each Phosphorus atom needs 3 more electrons to become stable like Noble Gas. Meaning P wants a total of 8 valence electrons. So if it has 5, it needs 3 more to have a total of 8.
Zn3P2 is an Ionic compound. In the compound, there are 3 atoms of Zn, and 2 of P. If 1 atom of P needs 3 valence electrons, then 2 atoms of P will need 6 valence electrons. There are 3 atoms of Zn, that means each Zinc atom has 2 valence electrons. So, the number of atoms times the number of valence electrons is 6 valence electrons. 3(2) = 6. This 6 valence electron goes to P2 because P2 needs 6 valence electrons. So the net charge is 0.
So, based on all of those each Zinc atom loses 2 valence electrons.