Answer:
La constante de equilibrio (K) se expresa como la relación entre las concentraciones molares (mol/l) de reactivos y productos. Su valor en una reacción química depende de la temperatura, por lo que ésta siempre debe especificarse.
Explanation:
<h3>
Answer:</h3>
4 cm³
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtract Property of Equality
<u>Chemistry</u>
<u>Gas Laws</u>
Density = Mass over Volume
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
D = 25 g/cm³
m = 100 g
<u>Step 2: Solve for </u><em><u>V</u></em>
- Substitute variables [D]:

- Multiply <em>V</em> on both sides:

- Isolate <em>V</em>:

A scale and a ruler. The scale to measure the mass, and a ruler to measure the volume.
The answer is: volume of ammonia gas is 7.4 L.
Chemical reaction: 6NO + 4NH₃ → 5N₂ + 6H₂O.
m(NO) = 15 g; mass of nitrogen(II) oxide.
M(NO) = 30 g/mol; molar mass of nitrogen(II) oxide.
V(NH₃) = ?
n(NO) = 15 g ÷ 30 g/mol.
n(NO) = 0.5 mol; amount of nitrogen(II) oxide.
From chemical reaction: n(NO) : n(NH₃) = 6 : 4.
0.5 mol : n(NH₃) = 6 : 4.
n(NH₃) = 0.33 mol; amount of ammonia.
Vm = 22.4 L/mol; molar volume at STP.
V(NH₃) = 0.33 mol · 22.4 L/mol..
V(NH₃) = 7.4 L.