NaBr < H3O+1 = OH-1 < Na^+1 = Br^-1 < H2O
<span>Least is NaBr (100% dissolved so no NaBr remains, only Na^+1 and Br^-1 </span>
<span>H2O yields 10^-7 M H3O^+1 and 10^-7 M OH^-1 (Kw = 1x10^-14 = [H3O+][OH-] </span>
<span>Na^+1 and Br^-1 will bothe be 0.1 M </span>
<span>H2O is slightly less that 1000 g / L in a 0.1 M NaBr solution, so its concentration is about 55.5 M</span>
The best answer to the question that is being presented above would be letter b. A compound can only be separated into two or more pure substances by a chemical change. Mixtures can be separated without chemical change.
Answer : The steps for balancing a redox reaction using half reaction method will include the following steps :
1) Write the basic ionic form of the reaction equation.
2) Divide the equation into two separate half reaction which will have oxidation half and reduction half reactions.
3) Balance the atoms present in each half of the reactions except O and H atoms in the reaction.
4) Balance the oxygen atoms in the reduction half of the reaction by the addition of two water molecules in the given conditions of the reaction.
5) Balance the charges present in both the half reactions.
6) The two halves of the equations reduction and oxidation are added to complete the overall reactions. After the addition of two reaction halves, cancel the same number electrons on both sides. The net ionic equation can be written after this step.
7) Finally, Verify whether the equation consists of the same type, number of co-efficients, and charges on both sides of the equation.
I believe it's A. Nanotechnology.