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Rudiy27
3 years ago
15

Which of these can be a result of inflation?

Mathematics
1 answer:
sdas [7]3 years ago
6 0
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
Among the choices the one that can be a result of inflation is <span>The price of household items increases</span>
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A train travels from station A to station B. If the train leaves station A and makes 75 km/hr, it arrives at station B 48 minute
SSSSS [86.1K]

Answer:

  • A) 290 km
  • B) 4 hours
  • C) 72.5 km/h

Step-by-step explanation:

Let distance be d and time t

<u>At 75 km/h speed the distance is</u>

  • d = 75(t - 48 min) = 75(t - 48/60 hours)

<u>At 50 km/h speed the distance</u> is

  • d = 50t + 40

<u>Since the distance is same, we get the equation:</u>

  • 75(t - 48/60) = 50t + 40
  • 75t - 75*4/5 = 50t + 40
  • 75t - 60 = 50t + 40
  • 75t - 50t = 40 + 60
  • 25t = 100
  • t = 4 hours

<u>A) The distance between A and B</u>

  • d = 50*5 + 40 = 290 km

<u>B) Time is </u>

  • 4 hours as found above

<u>C) The speed = d/t</u>

  • Speed = 290/4 = 72.5 km/h

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3 years ago
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4 years ago
A _____________ places points on the opposite side like a mirrored image.
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3 years ago
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A box of 15 cookies costs $9.<br> MY<br> What is the cost for 1 cookie?
Nitella [24]

Answer: $0.6

Step-by-step explanation:

15cookies= $9

1 cookie = x

Cross multiply

15x= 9

Divide both sides by 15

x= 9/15= 3/5= $0.6

4 0
3 years ago
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Two different simple random samples are drawn from two different populations. The first sample consists of 30 people with 16 hav
Furkat [3]

Answer:

  • There is no significant evidence that p1 is different than p2 at 0.01 significance level.
  • 99% confidence interval for p1-p2 is  -0.171 ±0.237 that is (−0.408, 0.066)

Step-by-step explanation:

Let p1 be the proportion of the common attribute in population1

And p2 be the proportion of the same common attribute in population2

H_{0}: p1-p2=0

H_{a}: p1-p2≠0

Test statistic can be found using the equation:

z=\frac{p2-p1}{\sqrt{{p*(1-p)*(\frac{1}{n1} +\frac{1}{n2}) }}} where

  • p1 is the sample proportion of the common attribute in population1 (\frac{16}{30} =0.533)
  • p2 is the sample proportion of the common attribute in population2 (\frac{1337}{1900} =0.704)
  • p is the pool proportion of p1 and p2 (\frac{16+1337}{30+1900}=0.701)
  • n1 is the sample size of the people from population1 (30)
  • n2 is the sample size of the people from population2 (1900)

Then z=\frac{0.704-0.533}{\sqrt{{0.701*0.299*(\frac{1}{30} +\frac{1}{1900}) }}} ≈ 2.03

p-value of the test statistic is  0.042>0.01, therefore we fail to reject the null hypothesis. There is no significant evidence that p1 is different than p2.

99% confidence interval estimate for p1-p2 can be calculated using the equation

p1-p2±z*\sqrt{\frac{p1*(1-p1)}{n1}+\frac{p2*(1-p2)}{n2}} where

  • z is the z-statistic for the 99% confidence (2.58)

Thus 99% confidence interval is

0.533-0.704±2.58*\sqrt{\frac{0.533*0.467}{30}+\frac{0.704*0.296}{1900}} ≈ -0.171 ±0.237 that is (−0.408, 0.066)

7 0
3 years ago
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