Answer:
- A) 290 km
- B) 4 hours
- C) 72.5 km/h
Step-by-step explanation:
Let distance be d and time t
<u>At 75 km/h speed the distance is</u>
- d = 75(t - 48 min) = 75(t - 48/60 hours)
<u>At 50 km/h speed the distance</u> is
<u>Since the distance is same, we get the equation:</u>
- 75(t - 48/60) = 50t + 40
- 75t - 75*4/5 = 50t + 40
- 75t - 60 = 50t + 40
- 75t - 50t = 40 + 60
- 25t = 100
- t = 4 hours
<u>A) The distance between A and B</u>
<u>B) Time is </u>
<u>C) The speed = d/t</u>
- Speed = 290/4 = 72.5 km/h
Bro that stuff is really hard is this rocket science
Answer: $0.6
Step-by-step explanation:
15cookies= $9
1 cookie = x
Cross multiply
15x= 9
Divide both sides by 15
x= 9/15= 3/5= $0.6
Answer:
- There is no significant evidence that p1 is different than p2 at 0.01 significance level.
- 99% confidence interval for p1-p2 is -0.171 ±0.237 that is (−0.408, 0.066)
Step-by-step explanation:
Let p1 be the proportion of the common attribute in population1
And p2 be the proportion of the same common attribute in population2
: p1-p2=0
: p1-p2≠0
Test statistic can be found using the equation:
where
- p1 is the sample proportion of the common attribute in population1 (
)
- p2 is the sample proportion of the common attribute in population2 (
)
- p is the pool proportion of p1 and p2 (
)
- n1 is the sample size of the people from population1 (30)
- n2 is the sample size of the people from population2 (1900)
Then
≈ 2.03
p-value of the test statistic is 0.042>0.01, therefore we fail to reject the null hypothesis. There is no significant evidence that p1 is different than p2.
99% confidence interval estimate for p1-p2 can be calculated using the equation
p1-p2±
where
- z is the z-statistic for the 99% confidence (2.58)
Thus 99% confidence interval is
0.533-0.704±
≈ -0.171 ±0.237 that is (−0.408, 0.066)