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3 years ago

13

A racing car used 255 litres of fuel to complete a 340 km race. On average, how many litres of fuel did the care use every 100 k

m?

1 answer:

zhenek [66]3 years ago

3 0

The answer is 75 liters per 100km. If you divide 340 by 100 you get 3.4 and then divide 255 by 3.4 you get 75.

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The first three terms of a sequence are given. Round to the nearest thousandth (if necessary).

zalisa [80]

Answer: 272

Step-by-step explanation:

Let a1=11

a2=20

a3=29

Formula for sequence=

an=a1+(n-1)d

an = nth term

a1= first term

n= nth position

d= common difference

We are looking for the 30th term,so our n=30

d= a2-a1

d= 20-11

d= 9

Using the formula

an= a1+(n-1)d

a30= 11+(30-1)9

a30= 11+(29)9

a30= 11+(29×9)

a30= 11+261

a30= 272

Therefore, the 30th term is 272

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3 years ago

What is the percent decrease if the number of student is 80 and now its 64.

Neporo4naja [7]

Answer:

.2

Step-by-step explanation:

When you do 64/80 you get 0.8 which means that the percent decrease is .2

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2 years ago

Read 2 more answers

A 6 sided die is roller 4 times in a row. The probability of getting a 4 only on the last trial

yanalaym [24]

The answer would be 1 of 6

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3 years ago

Multiple Representations:Question 1

alexdok [17]

Answer:

y = 27.1

Step-by-step explanation:

We have the value of x:

x = 12

and we need to find the value of y in the expression:

y = x + 15.1

as we can see by the equation, the value of y depends on the value of x.

thus, we substitute x = 12 on the previous equation:

y = 12 + 15.1

y = 27.1

the value of y is 27.1

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2 years ago

Which number line represtents the solution to |x+4|=2?

vlada-n [284]

Answer:

Points -2 and -6 on the number line are the two solutions.

Step-by-step explanation:

Use the definition of absolute value as a starting point

$|x|=x\,\,\mbox{for}\,\,x\geq 0\\|x|=-x\,\,\mbox{for}\,\,x$

To solve the equation, you need to treat the two cases as above:

$|x+4|=x+4=2\,\,\,\mbox{for}\,\,x+4\geq 0\implies x\geq -4\\x+4=2\implies x=-2$

The solution x=-2 is consistent with the condition x>=-4, so it is the first and valid solution. Now the second case of the absolute value:

$|x+4|=-(x+4)=2\,\,\,\mbox{for}\,\,x+4< 0\implies x$

Again, the second solution -6 complies with the requirement that x<-4, so it is valid.

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2 years ago