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Naya [18.7K]
3 years ago
5

to find area of a triangle you can use the Expression B * h / 2 where B is the base of the triangle and H is its height what is

the area of a triangle with a base of 6 and a height of 8
Mathematics
2 answers:
Vladimir [108]3 years ago
7 0
If the base is 6 and the height is 8, then 6x8=48
Divide by 2  (x half)
24 should be the answer
Nataliya [291]3 years ago
3 0
If base is 6 and height is 8. You would A=1/2(6x8) multiply and get 48 and then divide by 2 and get 24 as your answer
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This is a repeating number so i believe its rational
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Bag A: Two thirds of the candies are yellow. What portion of the candies is green
dalvyx [7]

Answer: \frac{1}{3} proportion of candies are green.  

Solution:  

In bag A, \frac{2}{3} candies are yellow.  

\frac{2}{3} this proportion shows ratio of favorable over total candies.  

Here numerator number is 2.  

So, Total number of yellow candies should be 2x

Total number of candies in Bag A would be 3x

Number of green candies in bag A = 3x-2x = x

Now we find the portion of green candies in bag A

\therefore,  \frac{x}{3x}

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7 0
3 years ago
Help!!!! Please just number 11 worth 90 points!!!!!
timurjin [86]

Answer:

6.75 hrs are missing

Step-by-step explanation:

First, change all fractions into decimals:

8 = 8

7 1/4 = 7 + 0.25 = 7.25

8 1/2 = 8 + 0.50 = 8.50

Next, add all numbers gotten together:

8 + 7.25 + 8.50 = 23.75

Subtract the number gotten from the total

30.5 - 23.75 = 6.75

~


3 0
3 years ago
Read 2 more answers
Assume that the flask shown in the diagram can be modeled as a combination of a sphere and a cylinder. Based on this assumption,
kompoz [17]

If the flask shown in the diagram can be modeled as a combination of a sphere and a cylinder, then its volume is

V_{flask}=V_{sphere}+V_{cylinder}.

Use following formulas to determine volumes of sphere and cylinder:

V_{sphere}=\dfrac{4}{3}\pi R^3,\\ \\V_{cylinder}=\pi r^2h,

wher R is sphere's radius, r - radius of cylinder's base and h - height of cylinder.

Then

  • V_{sphere}=\dfrac{4}{3}\pi R^3=\dfrac{4}{3}\pi \left(\dfrac{4.5}{2}\right)^3=\dfrac{4}{3}\pi \left(\dfrac{9}{4}\right)^3=\dfrac{243\pi}{16}\approx 47.71;
  • V_{cylinder}=\pi r^2h=\pi \cdot \left(\dfrac{1}{2}\right)^2\cdot 3=\dfrac{3\pi}{4}\approx 2.36;
  • V_{flask}=V_{sphere}+V_{cylinder}\approx 47.71+2.36=50.07.

Answer 1: correct choice is C.

If both the sphere and the cylinder are dilated by a scale factor of 2, then all dimensions of the sphere and the cylinder are dilated by a scale factor of 2. So

R'=2R, r'=2r, h'=2h.

Write the new fask volume:

V_{\text{new flask}}=V_{\text{new sphere}}+V_{\text{new cylinder}}=\dfrac{4}{3}\pi R'^3+\pi r'^2h'=\dfrac{4}{3}\pi (2R)^3+\pi (2r)^2\cdot 2h=\dfrac{4}{3}\pi 8R^3+\pi \cdot 4r^2\cdot 2h=8\left(\dfrac{4}{3}\pi R^3+\pi r^2h\right)=8V_{flask}.

Then

\dfrac{V_{\text{new flask}}}{V_{\text{flask}}} =\dfrac{8}{1}=8.

Answer 2: correct choice is D.


8 0
3 years ago
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