All categories

3 years ago

Someone please help me.

Mathematics

1 answer:

tiny-mole [99]3 years ago

3 0

Diameter = 14

Radius = 14 ÷ 2 = 7

Area = π.r²

Area = 7².π

Area = 49π

You might be interested in

Over the past several years, the proportion of one-person households has been increasing. The Census Bureau would like to test t

Ganezh [65]

Answer: z =2.39

Step-by-step explanation:

Given :

$H_0: p \leq0.23\\\\ H_a: p > 0.23$

A random sample of 136 households found that 43 consisted of one person.

i.e. Sample size : n= 136

Sample proportion : $\hat{p}=\dfrac{43}{136}=0.316176470588\approx0.3162$

Test statistic for proportion :-

$z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}$

$\Rightarrow z=\dfrac{0.3162-0.23}{\sqrt{\dfrac{0.23(1-0.23)}{136}}}\\\\\Rightarrow\ z=\dfrac{0.0862}{\sqrt{0.00130220588235}}\\\\\Rightarrow\ z=\dfrac{0.0862}{0.0360860898734}\\\\=2.38873206552\approx2.39$

Hence, the value of the test statistic: z =2.39

5 0

3 years ago

Find the area of a rectangle that is 7 cm long and 3 cm wide. You can use the tool to help you solve. 7 cm2 10 cm2 20 cm2 21 cm2

stiks02 [169]

Answer:

21sq

Step-by-step explanation:

multiply the l times the w which would be 3x7 and get 21.

8 0

3 years ago

Let the graph of g be a vertical stretch by a factor of 3 and a reflection in the y axis, followed by a translation 2 units left

forsale [732]

Answer:

First, let's write the general transformations:

a) A vertical stretch by a factor of 3.

f(x) ---> 3*f(x)

b) A reflection in the y-axis.

3*f(x) ----> 3*f(-x)

c) A translation of 2 units to the left.

3*f(-x) ----> 3*f(-x + 2)

then we know that:

g(x) = 3*f(-x + 2)

and f(x) = x^2 - x + 1

Then:

g(x) = 3*( (-x + 2)^2 - (-x + 2) + 1)

g(x) = 3*( x^2 - 4*x + 4 +x - 2 + 1) = 3*(x^2 - 3*x + 3)

g(x) = 3*x^2 - 9*x - 9

8 0

3 years ago

9. What's the least common multiple (LCM) of 2, 6, and 8?

algol [13]

Answer:

Step-by-step explanation:

The LCM or least common multiple of these numbers is 24

To get 24, you list all the multiple of these numbers until they all share at least one

2, 4, 6, 8, 10, 12, 14, 16, 18, 20, 22, 24

6, 12, 18, 24

8, 16, 24

They all share 24 so this is the LCM

Hope this helps

-GoldenWolfX

3 0

3 years ago

Given △ABC where A(2, 3), B(5, 8), C(8, 3), RS is the midsegment parallel to AC, ST is the midsegment parallel to AB, and RT is

soldier1979 [14.2K]

Since RS is a midsegment parallel to AC, that means R is the midpoint of AB and S is the midpoint of BC. The midpoint formula is:
$(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})$ . Using the coordinates of A and B, we have:
$R=(\frac{5+2}{2},\frac{8+3}{2})
\\R=(\frac{7}{2},\frac{11}{2})
\\R=(3.5, 5.5)$ . Similarly, S is the midpoint of BC:
$S=(\frac{5+8}{2},\frac{8+3}{2})
\\S=(\frac{13}{2},\frac{11}{2})
\\S=(6.5, 5.5)$ .
Since ST is a midsegment parallel to AB, then T must be a midpoint of AC:
$T=(\frac{2+8}{2},\frac{3+3}{2})
\\T=(\frac{10}{2},\frac{6}{2})
\\T=(5,3)$ .
Now that we have the coordinates of each point we can find the length of each segment using the distance formula:
$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$
For ST:
$d=\sqrt{(6.5-5)^2+(5.5-3)^2}
\\=\sqrt{(1.5)^2+(2.5)^2}
\\=\sqrt{2.25+6.25

\\=\sqrt{8.5}=2.9 \neq 4$
For RT:
$d=\sqrt{(3.5-5)^2+(5.5-3)^2}
\\=\sqrt{(-1.5)^2+(2.5)^2}
\\=\sqrt{2.25+6.25}
\\=\sqrt{8.5}=2.9 \neq 5$
For RS:
$d=\sqrt{(3.5-6.5)^2+(5.5-5.5)^2}
\\=\sqrt{(-3)^2+(0)^2}
\\=\sqrt{9+0}=\sqrt{9}=3$

6 0

3 years ago