The product of three whole numbers is 120 how many different possibilities are there for the three whole numbers
2 answers:
We can factor 120 into 2 * 2 * 2 * 3 * 5 I think there are nine different possibilities 1) 8 * 3 * 5 2) 4 * 2 * 15 3) 4 * 6 * 5 4) 4 * 10 * 3 5) 2 * 2 * 30 6) 2 * 3 * 20 7) 2 * 5 * 12 8) 2 * 6 * 10 9) 2 * 15 * 4
Solution:
It is given that,
Product of three Whole numbers = 120
Factorizing 120 into Prime Factors
120 = 2 ×2 ×2×3×5
Number of Possibilities
=Arrangement of 5 things which are numbers(2,2,2,3,5) when 3 of them are equal
=
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m = 56
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