1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
vlabodo [156]
3 years ago
12

V=1/3 pie r squared h

Mathematics
1 answer:
kvasek [131]3 years ago
7 0
This is volume of a sphere.
You might be interested in
Help please i need it
ValentinkaMS [17]

9514 1404 393

Answer:

  • the shape is a trapezoid
  • use the area formula
  • 48783 mm²

Step-by-step explanation:

The top and bottom edges are parallel, and the shape has 4 sides. That means it is a trapezoid. The area can be found using the formula for the area of a trapezoid:

  A = 1/2(b1 +b2)h

  A = 1/2(85 mm + 218 mm)(322 mm) = 1/2(303)(322) mm² = 48783 mm²

5 0
3 years ago
To solve a problem, we often _ _ _ _ _ _ _ _ _ the given information into algebraic expressions and equations
kogti [31]
To solve a problem, we often plug in the given information into algebraic expression and equations.
6 0
3 years ago
How do I solve this algebra two btw
pychu [463]

\bf \begin{cases} x^2+y^2=400\\ \boxed{y}=x-28 \end{cases}\qquad \stackrel{\textit{substituting on the 1st equation}}{x^2+\left( \boxed{x-28} \right)^2=400} \\\\\\ x^2+(x^2-56x+28^2)=400\implies x^2+x^2-56x+28^2=400 \\\\\\ 2x^2-56x+784=400\implies 2x^2-56x+384=0 \\\\\\ 2(x^2-28x+192)=0\implies x^2-28x+192=0 \\\\\\ (x-16)(x-12)=0\implies x = \begin{cases} 16\\ 12 \end{cases}

now that we know what are the x-values, what are the y-values? well, we can just use the 2nd equation, since we know that y = x - 28, then

\bf y = x - 28\implies \stackrel{\textit{when x = 16}}{y = 16 - 28}\implies y = -12 \\\\\\ y = x - 28\implies \stackrel{\textit{when x = 12}}{y = 12 - 28}\implies y = -16 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill (\stackrel{x}{16}~~,~~\stackrel{y}{-12})\qquad,\qquad (\stackrel{x}{12}~~,~~\stackrel{y}{-16})~\hfill

7 0
2 years ago
What's the Answer someone please help
Novay_Z [31]
Step 3: the student missed +4 in the equation while adding both equation

3 0
2 years ago
JK in the coordinate plane has endpoints with coordinates (-4, 11) and (8,
atroni [7]

Answer:

(0, 7)

Step-by-step explanation:

Given:

J(-4, 11)

K(8, -1)

JP:JK = 1/3

Required:

Coordinates of P

SOLUTION:

Use the formula, (x, y) = (x_1 + k(x_2 - x_1), y_1 + k(y_2 - y_1)) to find the coordinates of point P, that partition the segment JK into the ratio 1/3.

Let,

J(-4, 11) = (x_1, y_1)

K(8, -1) = (x_2, y_2)

k = \frac{1}{3}

Thus, plug in the values as follows:

P(x, y) = (-4 + \frac{1}{3}(8 -(-4)), 11 + \frac{1}{3}(-1 - 11)

P(x, y) = (-4 + \frac{1}{3}(12), 11 + \frac{1}{3}(-12)

P(x, y) = (-4 + \frac{12}{3}, 11 + \frac{-12}{3})

P(x, y) = (-4 + 4,  11 + (-4)

P(x, y) = (0, 7)

The coordinates of point P, are (0, 7)

3 0
3 years ago
Other questions:
  • Taylor drove from Tampa to New Orleans; her trip took her a total of 9.5 hours. Her average speed for the drive was 69 mph. For
    14·1 answer
  • Determine the quotient of 1 3/4 divide by 2/5
    11·2 answers
  • D <2? Don't mind the answer that was already on there?
    15·1 answer
  • Find the sum of the infinite geometric series, if it exists. 4 - 1 + 1/4 -1/6 +....
    9·2 answers
  • Earth has been charted with vertical and horizontal lines so that points can be named with coordinates. The horizontal lines are
    10·2 answers
  • Can you please help me with the problem in the image below?
    12·1 answer
  • Simplify the ratio /. Use the conversion 4 qt = 1 gal
    9·1 answer
  • What is the area of the window shown? Use 3.14 for pi.
    5·1 answer
  • Let v =LeftAngleBracket negative 10, 15 RightAngleBracket. What is the approximate direction angle of One-halfv? 34° 56° 124° 30
    10·2 answers
  • Evaluate 7p+6(p/q)2 q if p = 6 and q = 3. show your work and give an explanation for each step .
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!