Question

Gloria had two sets of alphabet cards (A–Z). She mixed the two sets together to form a single stack of cards. Then Gloria drew three cards from the stack without replacing them. What is the probability that she drew either a card with an L or a card with an R all three times?

Answer 1

She has 52 card all together so she has a probability of drawing on the first draw 4 L's or R's because their are two sets of alphabet cards.  So that is 4/52 or 1/13 to the lowest term.  Second turn she only has 51 cards to draw from and still has 4 L's and R's so that would be 4/51 and on the third try she has only 50 cards left so that would be 4/50 or 2/25 to the lowest term.  Now multiply all three factions 1/13 x 4/51 x 2/25 = 8/16575 meaning out of the three draws she has a probability of getting a L or R, 8 out of 16575 each draw.