A strontium hydroxide solution is prepared by dissolving 21.78 g of strontium hydroxide in water to make 75.00 mL of solution. W

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A strontium hydroxide solution is prepared by dissolving 21.78 g of strontium hydroxide in water to make 75.00 mL of solution. W

hat is the molarity of this solution? Next the strontium hydroxide solution prepared in part A is used to react with a 0.250 M nitric acid solution. Write a balanced chemical equation to represent the reaction between the strontium hydroxide and nitric acid solutions. How many milliliters of the nitric acid solution from part B (0.250 M) is needed to completely react 34.21 mL of the strontium hydroxide solution from part A?

Chemistry

2 answers:

Ludmilka [50] · Answer 1 · 2022-07-15T01:50:27+03:00

Chemical reaction: Sr(OH)₂ + 2HNO₃ → Sr(NO₃)₂ + 2H₂O.
part A) m(Sr(OH)₂) = 21,78 g.
n(Sr(OH)₂) = m(Sr(OH)₂) ÷ M(Sr(OH)₂).
n(Sr(OH)₂) = 21,78 g ÷ 87,62 g/mol.
n(Sr(OH)₂) = 0,248 mol.
c(Sr(OH)₂) = n(Sr(OH)₂) ÷ V(Sr(OH)₂).
c(Sr(OH)₂) = 0,248 mol ÷ 0,075 L.
c(Sr(OH)₂) = 3,3 mol/L.
part B) V(Sr(OH)₂) = 34,21 mL = 0,03421 L.
n(Sr(OH)₂) = 0,03421 L · 3,3 mol/L = 0,112 mol.
From chemical reaction: n(Sr(OH)₂) : n(HNO₃) = 1 : 2.
n(HNO₃) = 0,225 mol.
V(HNO₃) = 0,225 mol ÷ 0,25 mol/L.
V(HNO₃) = 0,9 L = 900 ml.

IRISSAK [1] · Answer 2 · 2022-07-15T03:35:58+03:00

Molarity Sr (OH)₂ : <u>2,387 M</u>

Milliliters of HNO₃ : <u>653.27 ml</u>

<h3>Further explanation</h3>

Stoichiometry in Chemistry learn about chemicals mainly emphasizes quantitative, such as the calculation of volume, mass, number, which is related to numbers, molecules, elements, etc.

A reaction coefficient is a number in the chemical formula of a substance involved in the reaction equation. The reaction coefficient is useful for equalizing reagents and products