Answer:
d
Explanation:
nCl2 = 0,1 -> nRCI = 0,2
M muéi = R + 35,5 = 14,9/0,2
-> R = 39: R la K
5.00<span> g x (1 mol/ 122.55 </span>g<span> ) = 0.0408 mol of </span>KClO3<span> in the </span><span>decomposition</span>
Specialized cell junctions occur at points of cell-cell and cell-matrix contact in all tissues.<span>
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