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soldier1979 [14.2K]
3 years ago
8

Complete the following.

Mathematics
1 answer:
Otrada [13]3 years ago
4 0

Answer:

Step-by-step explanation:

1) the triangle is a right angle triangle.

From the given right angle triangle,

With 67° as the reference angle,

x represents the adjacent side of the right angle triangle.

17 represents the opposite side of the right angle triangle.

To determine x, we would apply

the Tangent trigonometric ratio.

Tan θ = opposite side/adjacent side.

Therefore,

Tan 67 = 17/x

xTan 67 = 17

x = 17/Tan 67

x = 17/2.3559

x = 7.22

2) From the given right angle triangle, with 24° as the reference angle,

x represents the opposite side of the right angle triangle.

12 represents the adjacent side of the right angle triangle.

To determine x, we would apply

the Tangent trigonometric ratio.

Tan θ = opposite side/adjacent side.

Therefore,

Tan 24 = x/12

x = 12Tan 24

x = 12 × 0.4452

x = 5.34

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3 years ago
17/18 - 8/9 equal out to
Nutka1998 [239]
\frac{17}{18}-\frac{8}{9}=x
You must find a common denominator(bottom)
\frac{8}{9}×\frac{2}{2}=\frac{16}{18}
\frac{17}{18}-\frac{16}{18}=\frac{1}{18}
Your answer is x=\frac{1}{18}
8 0
3 years ago
To mix plaster for a dental model, 35 mL of water is used for 100g of plaster. How many mL of water should be used for 250g of p
laila [671]

Okay, here we have this:

Considering the provided information, we are going to calculate the requested value, so we obtain the following rule of three:

\begin{gathered} \frac{x}{35mL\text{ of water}}=\frac{250g\text{ of plaster}}{100g\text{ of plaster}} \\ x=\frac{250g\text{ of plaster}}{100g\text{ of plaster}}\cdot35mL\text{ of water} \end{gathered}

Solving for x:

\begin{gathered} x=2.5\cdot35mL\text{ of water} \\ x=87.5mL\text{ of water} \end{gathered}

Finally we obtain that 87.5mL of water should be used for 250g of plaster.

3 0
1 year ago
Which angle do ΔEBC and ΔADC share?
BARSIC [14]

Answer:

The angle in C

Step-by-step explanation:

6 0
2 years ago
NEED HELP QUICK!!
sashaice [31]

Answer:

Y = negative x + 9

Step-by-step explanation:

Find the equation of the line for side S-

m= 4-1/1-4 = 3/-3 = -1

<u>The Gradient is -1</u>

Since parallel lines share the same gradient, it should be either of the first two options.

We can see side Q shares the same gradient: 3-6/6-3= -1

Find the equation of the line of side Q-

y-y1= m(x-x1)

y-6= -1(x-3)

y-6=-x+3

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2 years ago
Read 2 more answers
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