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Bumek [7]
3 years ago
6

Josie found that 3.28+3.28+3.28= 9.84, what is the missing factor in the related multiplication problem

Mathematics
2 answers:
Vikentia [17]3 years ago
8 0

Answer with explanation:

→3.28+3.28+3.28

3.28 is added three times.

So, we can write it as

=3 × 3.28

=9.84

You can solve the problem , without multiplying ,3.28 by 3 , that is add 3.28 three times.

3.28

3.28

3.28

+

------------

9.84

So, we have solved the problem by two ways,by Multiplication and Addition.

→If you solve it by multiplication , the missing factor will be =3 × 3.28

Which is equal to 3.

Art [367]3 years ago
4 0

The expression which is:

3.28 + 3.28 + 3.28 = 9.84

 

Is simply equivalent to the expression of thrice the value of 3.28 is equal to 9.84 or:

3 x 3.28 = 9.84

 

<span>The two are simply equal since in the 1st expression there are three 3.28 and in the 2nd expression there are also three 3.28.</span>

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What is the probability that a data value in a normal distribution is between a z-score of -1.32 and a z-score of -0.34 Round yo
Galina-37 [17]

We are asked to find the probability that a data value in a normal distribution is between a z-score of -1.32 and a z-score of -0.34.

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5 0
3 years ago
Leora wants to paint the nursery on her house. The nursery is an 8-by-13-foot rectangle, and the ceiling is 9 feet tall. There i
Anna007 [38]

Answer:

336 ft²

Step-by-step explanation:

The rectangle is   13  ft long  and  8 width  that means we have  two walls 8* 9   and  two walls  13*9

Total walls area is

2*8*9 + 2*13*9   =   144  + 234   =  378 ft²

then we subtrac  , areas of door, closet and windows

3 * 6.5  =  19,5 ft²

3 * 6,5  =  19,5 ft²

2 * 1,5   =   3   ft²

               42 ft²

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4 0
3 years ago
A cardboard box without a lid is to be made with a volume of 4 ft 3 . Find the dimensions of the box that requires the least amo
Blababa [14]

Answer:

<h2><em>2ft by 2ft by 1 ft</em></h2>

Step-by-step explanation:

Total surface of the cardboard box is expressed as S = 2LW + 2WH + 2LH where L is the length of the box, W is the width and H is the height of the box. Since the cardboard box is without a lid, then the total surface area will be expressed as;

S  = lw+2wh+2lh ... 1

Given the volume V = lwh = 4ft³ ... 2

From equation 2;

h = 4/lw

Substituting into r[equation 1;

S = lw + 2w(4/lw)+ 2l(4/lw)

S = lw+8/l+8/w

Differentiating the resulting equation with respect to w and l will give;

dS/dw = l + (-8w⁻²)

dS/dw = l - 8/w²

Similarly,

dS/dl = w  + (-8l⁻²)

dS/dw = w - 8/l²

At turning point, ds/dw = 0 and ds/dl = 0

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l = 8/w²  and w =8/l²

l = 8/(8/l² )²

l = 8/(64/I⁴)

l = 8*l⁴/64

l = l⁴/8

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l = ∛8

l = 2

Hence the length of the box is 2 feet

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2 = 8/w²

1 = 4/w²

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w = 2 ft

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4 = 2(2)h

4 = 4h

h = 1 ft

Height of the cardboard is 1 ft

<em>The dimensions of the box that requires the least amount of cardboard is 2ft by 2ft by 1 ft</em>

8 0
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