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Bumek [7]
3 years ago
6

Josie found that 3.28+3.28+3.28= 9.84, what is the missing factor in the related multiplication problem

Mathematics
2 answers:
Vikentia [17]3 years ago
8 0

Answer with explanation:

→3.28+3.28+3.28

3.28 is added three times.

So, we can write it as

=3 × 3.28

=9.84

You can solve the problem , without multiplying ,3.28 by 3 , that is add 3.28 three times.

3.28

3.28

3.28

+

------------

9.84

So, we have solved the problem by two ways,by Multiplication and Addition.

→If you solve it by multiplication , the missing factor will be =3 × 3.28

Which is equal to 3.

Art [367]3 years ago
4 0

The expression which is:

3.28 + 3.28 + 3.28 = 9.84

 

Is simply equivalent to the expression of thrice the value of 3.28 is equal to 9.84 or:

3 x 3.28 = 9.84

 

<span>The two are simply equal since in the 1st expression there are three 3.28 and in the 2nd expression there are also three 3.28.</span>

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Plz help don’t understand
saul85 [17]

Answer:

Step-by-step explanation:

every time x goes up 1,  y goes up 4  

x = 3  minus x = 2  is a delta (a change of 1)

x = 4  minus x = 3  is a delta (a change of 1)

x = 5  minus x = 4  is a delta (a change of 1)

       the delta x is ALWAYS 1 for this table you can always substract x's to find the delta     delta is symbolized by Δ      Δx  for the delta x

y = 7  minus y = 3  is a delta (a change of 4)

y = 11  minus y = 7  is a delta (a change of 4)

y = 15  minus y = 11  is a delta (a change of 4)

    the delta y is ALWAYS 4 for this table you can always substract y's to find the delta     delta is symbolized by Δ     Δy  for the delta y

the slope m = Δy / Δx      m = 4 / 1     m = 4

     y = mx + b             when x = 0    then  y = b   (called the y intercept)

so how do we find the y intercept?    

look at the pattern in the TABLE  Δx  and Δy

   when x = 1    y = (3 - 4)  = -1

             x = 0    y =( -1 - 4)   = -5

so       y = 4x - 5     is a line equation for the data in this table

                                I believe there are other forms for linear equations

                               I chose the y-intercept form

use the point slope equation

       (y - y1)  =  m(x - x1)            where (x1, y1)  are the coordinates of a point on  

                                                the line

       when you know the slope of the line and a point on the line

       as before

       m = (y2 - y1)  / (x2 - x1)          from the table

           = (7 - 3) / (3 - 2)                 still equals

           = 4/1  =  4        

        pick a point on the line    say x= 4 and y = 11    (4, 11)

       (y - y1)  =  m(x - x1)    

        y - 11   =   4(x - 4)              point slope form

         solving point slope form  for  y

        y  - 11  =   4x - 16               add 11 to both sides    

           y  =  4x - 5                    back to the y-intercept form

7 0
3 years ago
In how many arrangements can 3 boys and 4 girls stand in a row such that no two boys are together?
S_A_V [24]
The answer is C :)


C
6 0
4 years ago
Can you help meh answer for brianliest
Yakvenalex [24]

Answer:

1st One- 1 13/30

2nd One- 1 13/20

3rd One- 1/6

Step-by-step explanation:

Because yes

4 0
3 years ago
Read 2 more answers
An economy package of cups has 460 green cups. If the green cups are 20% of the total package, how many cups are in the package?
Oksi-84 [34.3K]
2300 cups because if 460 is 20%, multiply the 460 x 5 to get 100%
3 0
3 years ago
Polynomial of degree 4 has 1 positive real root that is bouncer and 1 negative real root that is a bouncer. How many imaginary r
Rainbow [258]

Answer:

<h3>The given polynomial of degree 4 has atleast one imaginary root</h3>

Step-by-step explanation:

Given that " Polynomial of degree 4 has 1 positive real root that is bouncer and 1 negative real root that is a bouncer:

<h3>To find how many imaginary roots does the polynomial have :</h3>
  • Since the degree of given polynomial is 4
  • Therefore it must have four roots.
  • Already given that the given polynomial has 1 positive real root and 1 negative real root .
  • Every polynomial with degree greater than 1  has atleast one imaginary root.
<h3>Hence the given polynomial of degree 4 has atleast one imaginary root</h3><h3> </h3>

8 0
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