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Damm [24]
3 years ago
14

Identify the transformations that describe the graph of an odd function. Select all that apply.

Mathematics
1 answer:
Marianna [84]3 years ago
8 0
<span>A function is said to be an odd Function is the graph of the function is symmetric with respect to the origin. A function is odd if and only if f(–x) = –f(x).

The transformations that describe the graph of an odd function includes:

1.) </span><span>180° rotation around the origin

2.) </span><span>reflection over the line y = x</span>
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How do you prove each of the following theorems using either a two-column, paragraph, or flow chart proof?
lilavasa [31]

All the theorems are proved as follows.

<h3>What is a Triangle ?</h3>

A triangle is a polygon with three sides , three vertices and three angles.

1. The Triangle sum Theorem

According to the Triangle Sum Theorem, the sum of a triangle's angles equals 180 degrees.

To create a triangle ABC, starting at point A, move 180 degrees away from A to arrive at point B.

We turn 180 degrees from B to C and 180 degrees from C to return to A, giving a total turn of 360 degrees to arrive to A.

180° - ∠A + 180° - ∠B + 180° - ∠C = 360°

- ∠A - ∠B  - ∠C = 360° - (180°+ 180°+ 180°) = -180°

∠A + ∠B  + ∠C = 180°

(Hence Proved)

2. Isosceles Triangle Theorem

Considering an isosceles triangle ΔABC

with AB = AC, we have by sine rule;

\rm \dfrac{sinA}{BC} =  \dfrac{sinB}{AC} =  \dfrac{sinC}{AB}\\

as AB = AC

sin B = sin C

angle B = angle C

3.Converse of the Isosceles theorem

Consider an isosceles triangle ΔABC with ∠B= ∠C, we have by sine rule;

\rm \dfrac{sinA}{BC} =  \dfrac{sinB}{AC} =  \dfrac{sinC}{AB}\\

as  ∠B= ∠C ,

AB = AC

4. Midsegment of a triangle theorem

It states that the midsegment of two sides of a triangle is equal to (1/2)of the third side parallel to it.

Given triangle ABC with midsegment at D and F of AB and AC respectively, DF is parallel to BC

In ΔABC and ΔADF

∠A ≅ ∠A

BA = 2 × DA, BC = 2 × FA

Hence;

ΔABC ~ ΔADF (SAS similarity)

BA/DA = BC/FA = DF/AC = 2

Hence AC = 2×DF

5.Concurrency of Medians Theorem

A median of a triangle is a segment whose end points are on vertex of the triangle and the middle point of the side ,the medians of a triangle are concurrent and  the point of intersection is inside the triangle known as Centroid .

Consider a triangle ABC , X,Y and Z are the midpoints of the sides

Since the medians bisect the segment AB into AZ + ZB

BC into BX + XB

AC into AY + YC

Where:

AZ = ZB

BX = XB

AY = YC

AZ/ZB = BX/XB = AY/YC = 1

AZ/ZB × BX/XB × AY/YC = 1 and

the median segments AX, BY, and CZ are concurrent (meet at point within the triangle).

To know more about Triangle

brainly.com/question/2773823

#SPJ1

8 0
1 year ago
PLEASE ANSWER CORRECTLY, DON'T JUST STEAL THE POINTS.
marin [14]
Since you're only asked the ordered pair of D'', it's much easier just to plot and reflect point D twice than to do that for all four points!

Remember that reflecting points is like putting a mirror at the line of reflection or flipping that point over at that line. The reflected point should be the same distance from the line of reflection as the original point.

1) Reflect D over the x-axis to get D'.
D is at (4,1). Draw a line that is perpendicular to the line of reflection and goes through D. D is as far from the line of reflection as D' should be on its other side (both are on that perpendicular line). Since D is 1 unit above the x-axis, that means D' is 1 unit below at (4, -1). See picture 1.

2) Reflect D' over <span>y=x+1 to get D''. 
D' is at (4, -1). Draw </span>y=x+1 and the line perpendicular to it going through D''. D'' is the same distance from the line of reflection on the other side. See picture 2. D'' is at (-2, 5).

Answer: D'' is at (-2, 5)

7 0
3 years ago
Simplify. <br><br> √25 - √40 ?<br> help please.
melomori [17]

Answer:

5-2√10

Step-by-step explanation:

5-2√10

break them down

√25=5

so 5-√40

then simplify

5-2√10

7 0
3 years ago
Read 2 more answers
Given mZ1= x° and m Z2 = (x +50)".
Tju [1.3M]

Given:

m∠1= x° and m∠2 = (x +50)°.

To find:

The value of x, m∠1 and m∠2.

Solution:

From the figure it is clear that, transversal side intersect the opposite sides which are parallel and form ∠1 and ∠2.

Sum of same sided interior angles is 180 degrees. So,

m\angle 1+m\angle 2=180^\circ

x^\circ+(x+50)^\circ=180^\circ

2x^\circ+50^\circ=180^\circ

2x^\circ=180^\circ-50^\circ

2x^\circ=130^\circ

Divide both sides by 2.

x^\circ=65^\circ

x=65

Now,

m\angle 1=65^\circ

m\angle 2=(65+50)^\circ=115^\circ

Therefore, the correct option is C.

5 0
3 years ago
Write an expression 6 more than 5 times a n
polet [3.4K]
5 + 6 hahahahaha hahhahhahaha
5 0
2 years ago
Read 2 more answers
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