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3 years ago

A rectangular table is fivetimes as long as it is wide. if the area is 80ftsquared,find the length and the width of the table.

1 answer:

3 0

A = L * W
A = 80
L = 5W

80 = W(5W)
80 = 5W^2
80/5 = W^2
16 = W^2
sqrt 16 = W
4 = W <=== width is 4 ft

L = 5W
L = 5(4)
L = 20 <=== length is 20 ft

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a taste test asks people from Texas and California which pasta they prefer, brand A or brand B. this table shows the results

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Answer:

Step-by-step explanation:

Two events A and B are independent when

$P(A|B)=P(A),$

where $P(A|B)$ is the probability that event A occurs given that event B has occured.

A = randomly selected person is from California

B = randomly selected person preferred brand A

A|B = being a person from California and preferring brand A.

Hence,

$P(A)=\dfrac{150}{275}=\dfrac{6}{11}\approx 0.55\\ \\P(B)=\dfrac{176}{275}=\dfrac{16}{25}=0.64\\ \\P(A|B)=\dfrac{96}{176}=\dfrac{6}{11}\approx 0.55$

Since $P(A)=P(A|B),$ events are independent.

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3 years ago

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Suppose that E and F are two events and that Upper N (Upper E and Upper F )N(E and F)equals=250250 and Upper N (Upper E )N(E)equ

Anika [276]

Answer:

the probability is 0.4642 (46.42%)

Step-by-step explanation:

for the events E and F such that

N(E ∩ F) = 250 and N(E) = 560

where N represents the number of elements in that set , we can use the theorem of Bayes for conditional probability .Then representing N total =N(E∪F) , we have that the probability is

P( F|E ) = P (E ∩ F)/ P(E) = [N(E ∩ F) / N total]/ [N(E) / N total ] = N(E ∩ F)/ N(E) = 250/560 = 0.4642 (46.42%)

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3 years ago

1 2/3 divided by 3/16

KATRIN_1 [288]

1 2/3 divided by 3/16

5/3 / 3/16

KCF (Keep, Change, Flip)

5/3 * 16/3

5 * 16 = 80

3 * 3 = 9

5/3 * 16/3 = 80/9

8 8/9

Hope this helps!

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3 years ago

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U/5+6=2 what is the answer

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You subtract 6 from both sides, and then multiply by 6 on both sides. You should get -20.

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4 years ago

A 12 foot ladder is leaning against a building. If the bottom of the ladder is sliding along the pavement directly away from the

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Using Pythagoras theorem, the top of the ladder moving down when the foot of the ladder is 3 feet from the wall is of -0.518 feet/sec.

Let distance from the wall to the foot of the ladder is 'x' feet and the height of the top of the ladder is 'y' feet.

Pythagoras theorem, $x^{2} + y^{2} = (12)^{2}$ --->(1)

Given, $\frac{dx}{dt}= 2feet/second$ at x=3

Put x=3 in Pythagoras theorem equation (1)

$(3)^{2} + y^{2} = 144$

$y^{2} = 144 - 9$

$y^{2}$ = 135

y = 11.61

Derive equation (1) w.r.t to 't'

$2x\frac{dx}{dt} + 2y\frac{dy}{dt} = 0$ ---->(2)

substitute the value of 'x', 'dx/dt' and 'y' in equation (2), we get the fast of the top of the ladder moving down when the foot of the ladder is 3 feet from the wall

$2(3)(2) + 2 (11.61)\frac{dy}{dt} = 0$