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DedPeter [7]
3 years ago
15

BRAINLIEST! ANSWERS on here are all wrong please very desperate will give anything for correct answer. Thanks

Mathematics
1 answer:
aliina [53]3 years ago
5 0

Answer: 1.C 2.B 3.C

Step-by-step explanation:

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Stella [2.4K]
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Step-by-step explanation:

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SOVA2 [1]
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masha68 [24]
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3 0
3 years ago
A random number is selected from the interval [6.35, 10]. Find the probability that the number is within a distance of 0.25 from
exis [7]

Let <em>X</em> be a random number selected from the interval. Then the probability density for the random variable <em>X</em> is

f_X(x)=\begin{cases}\dfrac1{10-6.35}=\dfrac1{3.65}\approx0.2740&\text{if }6.35\le x\le 10\\0&\text{otherwise}\end{cases}

8 and 10 are the only even integers that fit the given criterion (6 is more than 0.25 away from 6.35), so that we're looking to compute

P(|<em>X</em> - 8| < 0.25) + P(|<em>X</em> - 10| < 0.25)

… = P(7.75 < <em>X</em> < 8.25) + P(9.75 < <em>X</em> < 10.25)

… = P(7.75 < <em>X</em> < 8.25) + P(9.75 < <em>X</em> < 10)

(since P(<em>X</em> > 10) = 0)

… = 0.2740 (8.25 - 7.75) + 0.2740 (10 - 9.75)

… = 0.2055

6 0
3 years ago
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