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3 years ago

8

of all the whole numbers that divide evenly into two or more numbers the one with the highest value is called the _____________.

1 answer:

Vadim26 [7]3 years ago

3 0

Greatest common factor (GCF)

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What is the completely factored form of f(x)=x3−7x2+2x+4?

sladkih [1.3K]

Answer:

The Factored form is

$f(x)=(x-1)(x-3-\sqrt{13} )(x-3+\sqrt{13} )$

Step-by-step explanation:

Given;

$f(x)=x^{3} -7\times x^{2} +2x+4$

To solve for x we factorize the right side of

$f(x)=x^{3} -7\times x^{2} +2x+4$

Let Substitute x for various values to check whether remainder is zero.

$f(1)=1^{3} -7\times 1^{2} +2\times 1+4$

Hence $x-1$ is a factor of the function.

Do synthetic division to find the quotient

$1$ $1$ $-7$ $2$ $4$

$1$ $-6$ $-4$

_____________________

$1$ $-6$ $-4$ $0$

We get remainder 0 and quotient as,

$x^{2} -(6\times x)-4$

By using Quadratic Formula;

$x=\frac{-b\pm\sqrt{b^{2}-4ac } }{2a}$

Plug 'a' , 'b' and 'c' value from $x^{2} -(6\times x)-4$ equation,

$x=\frac{-(-6)\pm\sqrt{-6^{2}-(4\times1\times -4 )} }{2\times1}$

$x=\frac{6\pm\sqrt{36+16 } }{2}$

$x=\frac{6\pm\sqrt{52} }{2}$

$x=3+\sqrt{13}$ and $x=3-\sqrt{13}$

The values of 'x' are $1$ , $3+\sqrt{13}$ and $3-\sqrt{13}$

So the Factored form is

$f(x)=(x-1)(x-3-\sqrt{13} )(x-3+\sqrt{13} )$

7 0

3 years ago

Help! What is the answer?

spayn [35]

Answer:

(10,0)

Step-by-step explanation:

4x - 5y = 40

To find the x intercept, set y =0 and solve for x

4x - 0 = 40

4x= 40

Divide by 4

4x/4 = 40/4

x = 10

The x intercept is 10

(10,0)

3 0

3 years ago

Read 2 more answers

Math for college readiness question. please help

zavuch27 [327]

Answer: 3

Step-by-step explanation:

$(f \circ f)(2) = f(f(2)) = f(3) = \boxed 3$

3 0

3 years ago

For his book report, Bobby made color copies and black-and-white copies. The black-and-white copies cost $2.75 in all. The color

Feliz [49]

16, i think it is the right answer.

3 0

3 years ago

2/3(9a+18b)=6a+kb

bagirrra123 [75]

Answer:

4.) 12

Step-by-step explanation:

$\frac{2}{3} (9a + 18b) = 6a + kb \\ \\ \implies \: \frac{2}{3} \times 9a + \frac{2}{3} \times 18b = 6a + kb \\ \\ \implies \: { 6a} + 12b = 6a + kb \\ \\ \implies \: \cancel{ 6a} + 12b - \cancel{ 6a} = kb \\ \\ \implies \: 12b = kb \\ \\ \implies \: k = \frac{12\cancel b}{\cancel b} \\ \\ \huge \implies \: k = 12$

8 0

3 years ago