Answer:
c=16*pi
a=64*pi
Step-by-step explanation:
Answer:
0.13% of customers spend more than 46 minutes
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
![\mu = 40, \sigma = 2](https://tex.z-dn.net/?f=%5Cmu%20%3D%2040%2C%20%5Csigma%20%3D%202)
What percentage of customers spend more than 46 minutes?
This is 1 subtracted by the pvalue of Z when X = 46. So
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
![Z = \frac{46 - 40}{2}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7B46%20-%2040%7D%7B2%7D)
![Z = 3](https://tex.z-dn.net/?f=Z%20%3D%203)
has a pvalue of 0.9987
1 - 0.9987 = 0.0013
0.13% of customers spend more than 46 minutes
First you have to get the same variables on one side so you’d subtract 5.1w from both sides, making the equation -0.6w = -30
then you want to single out the variable, diving -0.6 on both sides making the new equation and the answer w = 50
hope this helps!
Point c is quadrant 2,point T is quadrant 1,point R is x axis , point h is quadrant 3
I believe the answer is 17