Given:
Population of a colony in 2000 = 250
Population of a colony in 2004 = 400
To find:
The average rate of change.
Solution:
Let y be the population of the colony at x year.
The population of a colony grows from 250 in the year 2000 to 400 in the year 2004. So, the two points are (2000,250) and (2004,400).
Formula for slope or average rate of change is
Therefore, the average rate of change of population is 37.5.
Answer:
The answer is A.) For each category, the observed frequency is at least 5.
Step-by-step explanation:
Just took the test.
3.2 goes in the first and second blank, 8.7 is the final answer
The following can be deduced from the expressions
m ∠ D = 4 × m ∠ A
m ∠ B = 3 × m ∠ A-12
Please note that the sum of angles in a triangle is 180 degress. Therefore,
M∠ A + m ∠ B + m ∠ D = 180equation(3)
Substitute for equation 1 and 2 in equation 3 as shown below
m ∠ A + 3 × m ∠ A - 12^0 + 4 x m ∠ A =180^0
m ∠ A + 3 × m ∠ A + 4 x m ∠ A = 180^0+12^0
8m ∠ A = 192^0
m ∠ A= 192^0/8
m ∠ A=24^0
Substitute for m∠A= 24 in equation 1 and 2 as shown below
m ∠ D = 4 × m ∠ A
m ∠ D = 4 × 24^0
m ∠ D = 96^0
m ∠ B = 3 × mA - 12^0
m ∠ B = 3 × 24^0 - 12
m ∠ B = 72^0 - 12^0
,
∠= °
∠= °
∠= °
Answer:
D,no if you graph both inequalitiesvon thevsame geaph ,you will get b =16
