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Nat2105 [25]
3 years ago
13

Need your help please legitimately

Mathematics
1 answer:
Alenkasestr [34]3 years ago
4 0

Answer:

hey

Step-by-step explanation:

did you find the answer

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Translate into an algebraic expression: If I travel d miles in h hrs downstream on a river with a current of c mph, what would m
xenn [34]

Answer:

The speed is still water is v = \frac{d}{h} - c.

Step-by-step explanation:

Dimentionally speaking, speed is distance divided by time. Since, the person is travelling downstream, absolute speed is equal to the sum of current speed and speed of the person regarding current. Both components are constant. That is:

c + v = \frac{d}{h}

Where:

c - Current speed, measured in miles per hour.

v - Speed of the person regarding current, measured in miles per hour.

d - Distance travelled downstream, measured in miles.

h - Time spent on travelling, measured in hours.

Speed in still water occurs when current speed is zero. Then, such variable is obtained after subtracting current speed on both sides of the expression. Hence:

v = \frac{d}{h} - c

The speed is still water is v = \frac{d}{h} - c.

4 0
3 years ago
Which of the following statements best describe tge positive solution of the equation x2=2
777dan777 [17]
X is obviously 1
1x2=2
Entao...(So...)
Please mark as brainliest
4 0
2 years ago
19. GEOMETRY CONNECTION
Paul [167]
The cylinder is 7.0771 centimeters tall

6 0
3 years ago
I AM IN A TEST AND I NEED THE ANSWER SOON!!! PLEASEE!!!<br><br> THANK YOU SO MUCH!!
mart [117]
Hello,

If Viviana has 2/5 of pasta to share with four friends, you should divide. First change 2/5 to a decimal, 0.4. Now divide 0.4 and 4.

Workspace:


2/5 = 0.4

4 / 0.4 -> 10

Workspace End

Correct Answer:

10

Hope this helps!!
Brainliest??
8 0
2 years ago
You are a traffic accident investigator. You have arrived at the scene of an accident. Two trucks of equal mass (3,000 kg each)
Kazeer [188]

Answer:

1) Kinetic energy of the truck 1 is 600,000 joules.

Kinetic energy of the truck 2 is 1,837,500 joules.

2 a)Potential energy of truck 1 is 646,800 Joules.

b) Energy lose by the truck 1 just got converted into heat and sound energy during the collision.

Step-by-step explanation:

Mass of the truck 1 and truck 2,m = 3000 kg

Velocity of the truck 1, v_1 = = 20 m./s

Velocity of the truck 2,v_2 = 35 m./s

1. Kinetic energy of the truck 1:\frac{1}{2}mv_{1}^2=\frac{1}{2}\times 3000 kg\times (20 m/s)^=600,000 joules

Kinetic energy of the truck 2:\frac{1}{2}mv_{2}^2=\frac{1}{2}\times 3000 kg\times (35 m/s)^=1,837,500 joules

2.a) Energy loose by the truck 1:

Initial height of the truck on the hill = 22 m

At that height potential energy will be maximum:

Potential energy of truck 1 at that height = mgh=3000\times 9.8 m/s^2\times 22 m=646,800 Joules

b) Energy lose by the truck 1 just got converted into heat and sound energy during the collision.

3 0
3 years ago
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