Ask question

Ask question

All categories

3 years ago

13

Describe the error in using the percent equation to answer the equation.

1 answer:

zhannawk [14.2K]3 years ago

5 0

The answer would 50.

You might be interested in

Position to term rule of 2, 6, 10, 14, 18<br><br> multiply by _____ and subtract by _____

andreyandreev [35.5K]

Answer:

Please check the explanation.

Step-by-step explanation:

Given the sequence

2, 6, 10, 14, 18

An arithmetic sequence has a constant difference and is defined as

$\:a_n=a_1+\left(n-1\right)d$

compute the differences of all the adjacent terms

$6-2=4,\:\quad \:10-6=4,\:\quad \:14-10=4,\:\quad \:18-14=4$

The difference between all the adjacent terms is the same.

Thus,

$d=4$

and

$a_1=2$

Therefore, the nth term is computed by:

$a_n=4\left(n-1\right)+2$

$a_n=4n-2$

Thus, position to term rule of 2, 6, 10, 14, 18 multiply by __4___ and subtract by __2__.

4 0

3 years ago

Transform the following polar equation into an equation in rectangular coordinates: r=2 cos theta A. x + y = 2 B. y = 2x C. x =

Mila [183]

$r=2\cos\theta$
$r^2=2r\cos\theta$
$\implies x^2+y^2=2x$
$x^2-2x+y^2=0$
$x^2-2x+1+y^2=1$
$(x-1)^2+y^2=1$

8 0

3 years ago

Read 2 more answers

Given: F(x) = 5x - 6 and G(x) = x - 4

fomenos

Answer:

Correct choice is $\dfrac{x+26}{5}$

Step-by-step explanation:

1. If $F(x)=5x-6,$ then you can find the inverse $F^{-1}(x):$

$y=5x-6,\\ \\5x=y+6,\\ \\x=\dfrac{y+6}{5},\\ \\F^{-1}(x)=\dfrac{x+6}{5}.$

2. If $G(x)=x-4,$ then

$y=x-4,\\ \\x=y+4,\\ \\G^{-1}(x)=x+4.$

3. Hence,

$G^{-1}(F^{-1}(x))=G^{-1}\left(\dfrac{x+6}{5}\right)=\dfrac{x+6}{5}+4=\dfrac{x+26}{5}.$

7 0

3 years ago

72 is the product of Mai's height and 6.<br>

7nadin3 [17]

Answer:

12

Step-by-step explanation:

72/6 = 12

Or 72= h*6

Be sure to mark me brainliest!

3 0

3 years ago

Read 2 more answers

Three fourths of college students use the Internet more than the library. Nine hundredths use the library more. How many times m

Leno4ka [110]

Division
4/3X 100/9 = 8 1/3

5 0

4 years ago