let two integers be x and y
A.T.Q
x+y= -3
or, x= -3-y(i)
and xy= -18
or,(-3-y)y= -18[by(i)]
or,- -3y-y²= -18
or,-y²= -18+3
or, -y²= -15
or, y²=15
therefore y=✓15
from (i)
x= -3-✓15
y=√15
Answer:
1/4 gallon of yellow of paint and none of the blue paint
Step-by-step explanation:
At x=2, y=4
At x=4, y=16
So the total change in y from x=2 to x=4 is 16-4=12
And since average rate of change = total change in y divided by total change in x within the same period, therefore the answer is 12/2 = 6
Hope that helps. Let me know if you have any questions.
You solve this by plugging one equation into the other. Usually you have to rewrite one equation to make this work. In this case I choose to rewrite y-4x=0 as y=4x.
After plugging it into the second, you get:
3x + 6*4x = 9 => 27x = 9 => x=1/3
Putting this solution back into y=4x gives us y=4/3
Answer:
The first term is 42.
Step-by-step explanation:
The common difference is 142 - 140 = 2 so we have
50th term = a1 + 2(50 -1) = 140 where a1 is the first term
a1 + 98 = 140
a1 = 140 - 98 = 42.