Answer:
90 red pens
Step-by-step explanation:
we need to find the least common multiple of the numbers 3 , 5 , 6 , 9
6 = 2 × 3
9 = 3²
then
LCM(3,5,6,9) = 2×5×3² = 2×5×9 = 90
The number 90 can be divided into 3 ,5 ,6 ,9 with no remainder
Therefore the pack must have 90 pens or a multiple of 90
For example 180 , 270 ...
Answer:
6.8%
Step-by-step explanation:
the question has no information about class size (no. of student in class)
assume no. of student is infinite
P(3brown out of 6) = 6C3 * P(brown)^3 * P(not brown)^3
= 20 * 0.004913 * 0.695789
= 0.06837
9x1=9
9-9(3n)
9-27n
Can’t be solved
Answer:
36
Step-by-step explanation:
