Answer:
See below
Step-by-step explanation:
22. 30 = 2 * 3 * 5
23. 126 = 2 * 3 * 3 * 7
24. 4900 = 2 * 2 * 5 * 5 * 7 * 7
25. 39204 = 2 * 2 * 3 * 3 * 3 * 3 * 11 * 11
26. There's no square number
27. The highest common factor are
30 is 5
126 is 7
4900 is 7
39204 is 11
28. The lowest common factor are
30 is 2
126 is 2
4900 is 2
39204 is 2
What about you? What did you get?
Correct Question: If m∠JKM = 43, m∠MKL = (8x - 20), and m∠JKL = (10x - 11), find each measure.
1. x = ?
2. m∠MKL = ?
3. m∠JKL = ?
Answer/Step-by-step explanation:
Given:
m<JKM = 43,
m<MKL = (8x - 20),
m<JKL = (10x - 11).
Required:
1. Value of x
2. m<MKL
3. m<JKL
Solution:
1. Value of x:
m<JKL = m<MKL + m<JKM (angle addition postulate)
Therefore:

Solve for x


Subtract 8x from both sides


Add 11 to both sides


Divide both sides by 2


2. m<MKL = 8x - 20
Plug in the value of x
m<MKL = 8(17) - 20 = 136 - 20 = 116°
3. m<JKL = 10x - 11
m<JKL = 10(17) - 11 = 170 - 11 = 159°
Number 2 is 20 number 3 is 11
Answer:
Probability p( selecting 8 cities alphabetically) = 2.48×10^-5
Step-by-step explanation:
Number of possible ways of choosing 8 cities=Permutation P(n,k) = n!/(n-k)!
P(8,8)= 8!/(8-8)! = 8! = 40,320
Probability (selecting 8 cities alphabetically) = 1/40320 = 2.48×10^-5