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Alex73 [517]
3 years ago
8

Last week Len spent $18 to bowl 4 games. This week he spent $27 to bowl 6 games Len owns his bowling ball and shoes, so he only

has to pay for each game that he bowls. If each of these bowling games costs the same amount of money, what is the constant of proportionality between the money spent and the number of games played?
Mathematics
1 answer:
DIA [1.3K]3 years ago
6 0
Basically you just have to do either $18/4 or $27/6 which gets you to 4.5 which is the unit rate
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Choose all the numbers that are common multiples of 3 and 12.
spayn [35]
<h3>Answers: 48 and 72</h3>

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Explanation:

The number 12 is a multiple of 3 because 3*4 = 12.

So when looking for common multiples of 3 and 12, we simply need to look at multiples of 12.

The multiples of 12 are:

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We see that 48 and 72 are on the list. The values 21, 27, 63, 81 are not on the list, so cross them out.

Now we could keep that list of multiples going to see if 844 is on there or not. A better method is to divide 844 over 12. If we get a whole number, then it's a multiple of 12.

844/12 = 70.333 approximately.

This shows that 844 is <u>not</u> a multiple of 12. So we cross 844 from the list.

Only 48 and 72 are multiples of 12 (and also multiples of 3).

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3 years ago
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Answer:

11:4

Step-by-step explanation:

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2 years ago
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Find the measure of &lt;BMD​ (please this is urgent)
Bogdan [553]

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3 years ago
Suppose that a school has 20 classes: 16 with 25 students in each, three with 100 students in each, and one with 300 students, f
astraxan [27]

Answer

a)   y    |      p(y)

    25   |      0.8

   100   |     0.15

   300   |      0.05

E(y) = ∑ y . p(y)

E(y) = 25 × 0.8 + 100 × 0.15 + 300 × 0.05

E(y) = 50

average class size equal to E(y) = 50

b)  y    |      p(y)

    25   |     \dfrac{16\times 25}{1000}=0.4

   100   |     \dfrac{3\times 100}{1000}=0.3

   300   |      \dfrac{1\times 300}{1000}=0.3

E(y) = ∑ y . p(y)

E(y) = 25 × 0.4 + 100 × 0.3 + 300 × 0.3

E(y) = 130

average class size equal to E(y) = 130

c) Average Student in the class in a school = 50

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