Let's call this line y=mx+C, whereby 'm' will be its gradient and 'C' will be its constant.
If this line is parallel to the line you've just mentioned, it will have a gradient 2/3. We know this, because when we re-arrange the equation you've given us, we get...

So, at the moment, our parallel line looks like this...
y=(2/3)*x + C
However, you mentioned that this line passes through the point Q(1, -2). If this is the case, for the line (almost complete) above, when x=1, y=-2. With this information, we can figure out the constant of the line we want to find.
-2=(2/3)*(1) + C
Therefore:
C = - 2 - (2/3)
C = - 6/3 - 2/3
C = - 8/3
This means that the line you are looking for is:
y=(2/3)*x - (8/3)
Let's find out if this is truly the case with a handy graphing app... Well, it turns out that I'm correct.
In order to find the answer to this question, you would need to find the Greatest Common Factor of 16 and 12 which would be 4 because 4 is the greatest amount that you can divide both 12 and 16 by. So the soonest both ships will leave together again will be in 4 days.
Answer:
~ <em>50 centimeters of the poster ~</em>
Step-by-step explanation:
Let us plan out our steps, and solve for each:
<em>1. Given the information, let us create a proportionality as such:</em>
<em />
5 = 1 ⇒ x - centimeters of the poster
x 10
<em>2. Now let us cross multiply, and solve through simple algebra for x:</em>
5 * 10 = x,
x =<em> 50 centimeters of the poster </em>
<em></em>
Step-by-step explanation:
here u go.
hope it helps you
3x - 15 = 105
3x = 120
x = 40
3(40) - 15 + y + 24 = 180
120 - 15 + y + 24 = 180
129 + y = 180
y = 51