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spin [16.1K]
3 years ago
13

Which equation has infinitely many solutions?

Mathematics
2 answers:
Verdich [7]3 years ago
5 0

Answer:

The second option (5x+14-4x=23+x-9)

Step-by-step explanation:

For an equation to have infinitely many solutions each side must be exactly the same when simplified.

12+4x=6x+10-2x

Combine alike terms.

12+4x=4x+10

Subtract 4x from each side

12=10

This is not true so this equation has no solutions.

5x+14-4x=23+x-9

Combine alike terms

x+14=14+x

subtract x from each side

14=14

This is true so this equation has infinitely many solutions.

Hope this helps! If you have any questions on how I got my answer feel free to ask. Stay safe!

koban [17]3 years ago
3 0

Answer:

your answer is correct

Step-by-step explanation:

5x+14-4x=23+x-9

simply both sides

x+14=x+14

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Which of the following functions are solutions of the differential equation y" + y = 7 sin(x)? (Select all that apply.)
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The homogeneous equation

y'' + y = 0

has characteristic equation

r² + 1 = 0

with roots at r = ± √(-1) = ± i, and so the characteristic solution is

y = C₁ cos(x) + C₂ sin(x)

Using the method of undetermined coefficients, suppose

y = a x cos(x) + b x sin(x)

(we would normally consider y = a cos(x) + b sin(x), but cos(x) and sin(x) are already part of the characteristic solution)

The derivatives are

y' = a cos(x) - a x sin(x) + b sin(x) + b x cos(x)

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and

y'' = -a sin(x) + (b - a x) cos(x) + b cos(x) - (a + b x) sin(x)

y'' = (-2a - b x) sin(x) + (2b - a x) cos(x)

Then

y'' + y = (-2a - b x) sin(x) + (2b - a x) cos(x) + a x cos(x) + b x sin(x)

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and it follows that a = -7/2 and b = 0.

So, the general solution to the DE is

y = C₁ cos(x) + C₂ sin(x) - 7/2 x cos(x)

which means the only valid solutions from the given choices are

y = 7 sin(x)

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4 0
2 years ago
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