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spin [16.1K]
3 years ago
13

Which equation has infinitely many solutions?

Mathematics
2 answers:
Verdich [7]3 years ago
5 0

Answer:

The second option (5x+14-4x=23+x-9)

Step-by-step explanation:

For an equation to have infinitely many solutions each side must be exactly the same when simplified.

12+4x=6x+10-2x

Combine alike terms.

12+4x=4x+10

Subtract 4x from each side

12=10

This is not true so this equation has no solutions.

5x+14-4x=23+x-9

Combine alike terms

x+14=14+x

subtract x from each side

14=14

This is true so this equation has infinitely many solutions.

Hope this helps! If you have any questions on how I got my answer feel free to ask. Stay safe!

koban [17]3 years ago
3 0

Answer:

your answer is correct

Step-by-step explanation:

5x+14-4x=23+x-9

simply both sides

x+14=x+14

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Find the cost of painting a cubical block of side length 3.2 cm, if painting costs $5 per cm2.
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<h3><u>Answer</u>:- </h3>

\longrightarrow \sf \$ \: 307.2

<h3><u>Solution:-</u></h3>

Since painting is done on outer surface of cubical block we will have to find its surface area which is given by-

\green{ \underline { \boxed{ \sf{Surface \: area  \:of  \:Cube = 6a^2}}}}

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\begin{gathered}\\\quad \sf Surface \: area  \:of  \:Cube = 6\times(3.2)^2  \\\end{gathered}

\begin{gathered}\\\implies \quad \sf  6\times 3.2\times3.2   \\\end{gathered}

\begin{gathered}\\\implies \quad \sf  61.44 cm^2  \\\end{gathered}

Now,

\maltese \sf Cost  \:of  \:painting \: 1 \: cm² = \$ 5

\sf Cost \: of \: painting \: 61.44  \:cm²=61.44×5

\sf\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad=\$ 307.2

\leadstoThus it would cost $ 307.2 to paint the entire cubical block.

3 0
2 years ago
See attachment for problem
Effectus [21]

The liters in the tank when it is filled to a height of 3.70 is  5,580 liters

The liters that needs to be added to 100% capacity is 480 liters

<h3>What is the volume?</h3>

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Volume of a cone = 1/3(πr²h)

Where:

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Volume of the right circular cone when its filled to a height of 3.70 = 1/3 x 3.14 x 3.70 x 1.20² = 5.58 m³

5.58 x 1000 = 5,580 liters

Volume of the right circular cone when it is full =  1/3 x 3.14 x 4 x 1.20² = 6.03  m³

6.03 x 1000 = 6030 liters

Liters that needs to be added to 100% capacity =  6030 liters - 5,580 liters  = 480 liters

To learn more about the volume of a cone, please check: brainly.com/question/13705125

#SPJ1

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Answer:

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Step-by-step explanation:

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