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nika2105 [10]
2 years ago
7

Nora is in the business of manufacturing phones. She must pay a daily fixed cost to rent the building and equipment, and also pa

ys a cost per phone produced for materials and labor. The labor and materials cost $150 for each phone manufactured, and the total cost of producing 8 phones in a day would be $2200. Write an equation for C, in terms of p, representing total cost, in dollars, of producing p phones in a given day.
Mathematics
1 answer:
vaieri [72.5K]2 years ago
5 0

9514 1404 393

Answer:

  c = 150p + 1000

Step-by-step explanation:

We know the variable cost is 150 per phone, so the total cost will be ...

  c = 150p +b . . . . for some value b

We also know the value of c for 8 phones, so we can find b:

  2200 = 150(8) + b

  2200 -1200 = b = 1000

Then the desired equation is ...

  c = 150p + 1000

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3 years ago
Find two consecutive odd integers such that their product is 71 more than 3 times their sum.
SVETLANKA909090 [29]
Let's put this in terms of a system of equations. Let's call the numbers x and y, with x being the larger integer and y the smaller one. Since they are consecutive odd integers, we know that:
x = y + 2
The constraint is:
xy= 3(x+y) + 71         Simplify
xy = 3x + 3y + 71       Plug in (y+2) for x:
(y + 2) y = 3(y + 2) + 3y + 71         Simplify
y² + 2y = 3y + 6 + 3y + 71              Subtract 6y from  both sides, add 71+6
y² -4y = 77
y² - 4y - 77 = 0
Factor:
(y - 11) (y+7) = 0
y = 11 or y=-7

When y = 11, x = 13, since x = y+2
Plug in to make sure:
xy = 3(x+y) + 71
11*13 = 3 (11 + 13) + 71
143 = 3 (24) + 71
143 = 72 + 71
143 = 143               
Our values work! 
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3 years ago
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Step-by-step explanation:

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Step-by-step explanation:

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