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nika2105 [10]
3 years ago
7

Nora is in the business of manufacturing phones. She must pay a daily fixed cost to rent the building and equipment, and also pa

ys a cost per phone produced for materials and labor. The labor and materials cost $150 for each phone manufactured, and the total cost of producing 8 phones in a day would be $2200. Write an equation for C, in terms of p, representing total cost, in dollars, of producing p phones in a given day.
Mathematics
1 answer:
vaieri [72.5K]3 years ago
5 0

9514 1404 393

Answer:

  c = 150p + 1000

Step-by-step explanation:

We know the variable cost is 150 per phone, so the total cost will be ...

  c = 150p +b . . . . for some value b

We also know the value of c for 8 phones, so we can find b:

  2200 = 150(8) + b

  2200 -1200 = b = 1000

Then the desired equation is ...

  c = 150p + 1000

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vekshin1
Sin(70+80) = sin 150.......................
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3 years ago
Use stoke's theorem to evaluate∬m(∇×f)⋅ds where m is the hemisphere x^2+y^2+z^2=9, x≥0, with the normal in the direction of the
ludmilkaskok [199]
By Stokes' theorem,

\displaystyle\int_{\partial\mathcal M}\mathbf f\cdot\mathrm d\mathbf r=\iint_{\mathcal M}\nabla\times\mathbf f\cdot\mathrm d\mathbf S

where \mathcal C is the circular boundary of the hemisphere \mathcal M in the y-z plane. We can parameterize the boundary via the "standard" choice of polar coordinates, setting

\mathbf r(t)=\langle 0,3\cos t,3\sin t\rangle

where 0\le t\le2\pi. Then the line integral is

\displaystyle\int_{\mathcal C}\mathbf f\cdot\mathrm d\mathbf r=\int_{t=0}^{t=2\pi}\mathbf f(x(t),y(t),z(t))\cdot\dfrac{\mathrm d}{\mathrm dt}\langle x(t),y(t),z(t)\rangle\,\mathrm dt
=\displaystyle\int_0^{2\pi}\langle0,0,3\cos t\rangle\cdot\langle0,-3\sin t,3\cos t\rangle\,\mathrm dt=9\int_0^{2\pi}\cos^2t\,\mathrm dt=9\pi

We can check this result by evaluating the equivalent surface integral. We have

\nabla\times\mathbf f=\langle1,0,0\rangle

and we can parameterize \mathcal M by

\mathbf s(u,v)=\langle3\cos v,3\cos u\sin v,3\sin u\sin v\rangle

so that

\mathrm d\mathbf S=(\mathbf s_v\times\mathbf s_u)\,\mathrm du\,\mathrm dv=\langle9\cos v\sin v,9\cos u\sin^2v,9\sin u\sin^2v\rangle\,\mathrm du\,\mathrm dv

where 0\le v\le\dfrac\pi2 and 0\le u\le2\pi. Then,

\displaystyle\iint_{\mathcal M}\nabla\times\mathbf f\cdot\mathrm d\mathbf S=\int_{v=0}^{v=\pi/2}\int_{u=0}^{u=2\pi}9\cos v\sin v\,\mathrm du\,\mathrm dv=9\pi

as expected.
7 0
3 years ago
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miss Akunina [59]

I think its 180/24 here is my work

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5 0
3 years ago
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irinina [24]

Answer:

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Step-by-step explanation:

Hope this helped :)

3 0
3 years ago
Which of the following is a polynomial with roots: − square root of 5 , square root of 5 , and −3?
tresset_1 [31]
Roots: - √5 , √5, and - 3

=> these are factors of the polynomial: (x + √5), (x - √5), and (x + 3).

Multiply those three factors:

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Therefore the polynomial x^2 + 3x^2 - 5x - 15 is a polynomial with the given roots.

Answer: option B. x^3 + 3x^2 - 5x - 15
4 0
3 years ago
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