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Vinvika [58]
3 years ago
11

2. The bottom of a ramp is placed 15 feet from the edge of a stage

Mathematics
1 answer:
Firdavs [7]3 years ago
8 0

Answer:

The slope of the ramp is 1.

Step-by-step explanation:

See the diagram attached.

Here, AC  = 15 ft. and ED = 5 ft. while AE = 10 ft.

Then, EC = (15 - 10) = 5 ft.

Now, considering the right triangle Δ EDC, if \theta is the inclination of the ramp, then \tan \theta = \frac{ED}{EC} = \frac{5}{5} = 1

Hence, \theta = 45 ^{\circ}

Therefore, the slope of the ramp is 1. (Answer)

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Which equation represents a circle with a center at (-4, 9) and a diameter of 10 units?
blsea [12.9K]

Answer:

(x+4)^2 + (y-9)^2 = 25

Step-by-step explanation:

We can use the equation (x-h)^2 + (y-k)^2 = r^2

where (h,k) is the center and r is the radius

The center is at (-4,9) and the diameter is 10 which means the radius is 10/2 or 5

(x- -4)^2 + (y-9)^2 = 5^2

(x+4)^2 + (y-9)^2 = 25

3 0
3 years ago
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Answer:

A

Step-by-step explanation:

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2 years ago
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r-ruslan [8.4K]

Answer:

The answer is B.It is one-half the area of a square of side length 4 units.

Step-by-step explanation:

Given a coordinate grid shown with triangle of measurements with base 4 units and height also 4 units.

We have to find the area of triangle which can be calculated as

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                 =  

we have to choose the statement describes the area of the triangle evaluate above.

Option A: Not matched ∵equals to [area of rectangle of length 4 units width 2 units]=                                    

Option B: matched : given one-half the area of a square of side length 4 units.

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Option C : Not matched : It is twice the area of a rectangle of length 4 units and width 2 units

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So, the correct option is B. It is one-half the area of a square of side length 4 units.

4 0
3 years ago
Read 2 more answers
The sides OP and RO of triangle POR are produced to points S and T respectively. If ∠SPR = 145° and ∠POT = 115° , find ∠PRO
Margarita [4]

Answer:

\angle PRQ = 80

Step-by-step explanation:

Given

\angle SPR = 145^o

\angle POT = 115^o

See attachment

Required

Find \angle PRO

First, calculate \angle RPO

\angle RPO + \angle SPR = 180 --- angle on a straight line

So, we have:

\angle RPO + 145 = 180

Collect like terms

\angle RPO = 180 - 145

\angle RPO = 35

Next, calculate PQR

\angle POR + \angle POT = 180

So, we have:

\angle POR + 115 = 180

Collect like terms

\angle POR = 180-115

\angle POR = 65

So, PRO is calculated as:

\angle PRO + \angle POR + \angle RPO = 180 --- angles in a triangle

So, we have:

\angle PRO + 65 + 35= 180

\angle PRO + 100= 180

Collect like terms

\angle PRO = 180-100

\angle PRO = 80

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3 years ago
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Ne4ueva [31]

Answer:

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Step-by-step explanation:

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