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miskamm [114]
3 years ago
5

Complete the problem to represent the situation given by the equation 0.40e + 10 + 15 = 0.20e + 5 + 25. At one store a trophy co

sts $15, initial engraving set-up cost $0.40 , and engraving costs $0.20 per letter. At another store, the same trophy costs $25 , initial engraving set-up costs $5, and engraving costs $10 per letter. How many letters, e, must be engraved for the costs to be the same?
Mathematics
2 answers:
olganol [36]3 years ago
8 0

Answer: The number of letters that must be engraved for the costs to be the same is 125.

Step-by-step explanation:

Since we have given that

0.4e+10+15=0.20e+5+25

We need to find the number of letters.

0.4e+25=0.2e+30\\\\0.4e-0.2e=30-25\\\\0.2e=25\\\\e=\dfrac{25}{0.2}\\\\e=125

Hence, the number of letters that must be engraved for the costs to be the same is 125.

Wewaii [24]3 years ago
3 0

Answer:

hi

Step-by-step explanation:

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