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miskamm [114]
3 years ago
5

Complete the problem to represent the situation given by the equation 0.40e + 10 + 15 = 0.20e + 5 + 25. At one store a trophy co

sts $15, initial engraving set-up cost $0.40 , and engraving costs $0.20 per letter. At another store, the same trophy costs $25 , initial engraving set-up costs $5, and engraving costs $10 per letter. How many letters, e, must be engraved for the costs to be the same?
Mathematics
2 answers:
olganol [36]3 years ago
8 0

Answer: The number of letters that must be engraved for the costs to be the same is 125.

Step-by-step explanation:

Since we have given that

0.4e+10+15=0.20e+5+25

We need to find the number of letters.

0.4e+25=0.2e+30\\\\0.4e-0.2e=30-25\\\\0.2e=25\\\\e=\dfrac{25}{0.2}\\\\e=125

Hence, the number of letters that must be engraved for the costs to be the same is 125.

Wewaii [24]3 years ago
3 0

Answer:

hi

Step-by-step explanation:

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Step by step explanation:      

Please find the attachment.

We have been given that line l_1 is horizontal and passes through point (1,1). Line l_2 is vertical and passes through point (2,2). We are asked to find point of intersection of line l_1 and line l_2.  

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5 0
3 years ago
the height of the snow was 84 inches in the beginning of the week. it melts at a rate of 0.15 inches per hour. how many hours wo
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It takes 147 hours for the snow to reach 62 inches.

Step-by-step explanation:

Given:

Height of the snow at the beginning  = 84 inches

Rate at which the snow melts = f 0.15 inches per hour

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