Answer:
B
Step-by-step explanation:
<span>(a) This is a binomial
experiment since there are only two possible results for each data point: a flight is either on time (p = 80% = 0.8) or late (q = 1 - p = 1 - 0.8 = 0.2).
(b) Using the formula:</span><span>
P(r out of n) = (nCr)(p^r)(q^(n-r)), where n = 10 flights, r = the number of flights that arrive on time:
P(7/10) = (10C7)(0.8)^7 (0.2)^(10 - 7) = 0.2013
Therefore, there is a 0.2013 chance that exactly 7 of 10 flights will arrive on time.
(c) Fewer
than 7 flights are on time means that we must add up the probabilities for P(0/10) up to P(6/10).
Following the same formula (this can be done using a summation on a calculator, or using Excel, to make things faster):
P(0/10) + P(1/10) + ... + P(6/10) = 0.1209
This means that there is a 0.1209 chance that less than 7 flights will be on time.
(d) The probability that at least 7 flights are on time is the exact opposite of part (c), where less than 7 flights are on time. So instead of calculating each formula from scratch, we can simply subtract the answer in part (c) from 1.
1 - 0.1209 = 0.8791.
So there is a 0.8791 chance that at least 7 flights arrive on time.
(e) For this, we must add up P(5/10) + P(6/10) + P(7/10), which gives us
0.0264 + 0.0881 + 0.2013 = 0.3158, so the probability that between 5 to 7 flights arrive on time is 0.3158.
</span>
<h3>
Answer: 23.13 square meters</h3>
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Explanation:
The top and bottom semicircles can be joined to form a full circle. The same can be said about the left and right semicircles. Each circle has diameter 3 and radius 1.5
The area of one circle is
A = pi*r^2
A = 3.14*(1.5)^2
A = 7.065
So two circles doubles to 2*7.065 = 14.13 square meters in area.
Then the last step is to add on the area of the 3 by 3 square (area 3*3 = 9) to get 14.13+9 = 23.13
This area is approximate because pi = 3.14 is approximate. Use more decimal digits in pi to get a more accurate area. However, your teacher wants you to use this specific value so it's best to stick with 23.13
Answer:
(0,0), (1,1), (2,2)
Step-by-step explanation:
When testing to find possible points in situations like this, I always start by testing with the origin point (0,0).
In this case:
4x+6y<24 ==> 0 + 0 < 24 TRUE, it satisfies the inequality.
We then try with (1,1):
4x+6y<24 ==> 4 + 6 < 24 TRUE, it satisfies the inequality.
And with (2,2):
4x+6y<24 ==> 8 + 12 < 24 TRUE, it satisfies the inequality.
