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Rasek [7]
1 year ago
12

The student council is hosting a homecoming event for past graduates and current students. The treasurer determines that the eve

nt revenue from the event can be represented by R (z) = 0.05x³75, where x is the number of tickets sold. The cost to put on the event is represented by the function C(z) = 30x + 12,500. Which function describes the funds raised, F(x), as a function of the number of tickets sold? O F(z) F(x) F(x) 0.05³ +30 - 12, 425 F(x) 0.05z³ 30x - 12,425 O = 0.05³ +30 - = 12,575 = 0.05³ 30 - 12,575
Mathematics
1 answer:
xxTIMURxx [149]1 year ago
6 0

The function that describes the fund that was raised is 0.05³ - 30x - 12425

<h3>How to solve for the function</h3>

The revenue is  R (z) = 0.05x³ + 75

the cost = C(z) = 30x + 12,500.

Please note that the equation for revenue missed a sign in the question so I made use of the plus sign

We would have revenue - cost

Hence ( 0.05x³ + 75) - (30x + 12,500)

We would open the bracket

0.05x³ + 75 -30x -12500

We would take the like term to

0.05³ - 30x -12500 + 75

0.05³ - 30x - 12425

The function that describes the fund that was raised is 0.05³ - 30x - 12425

Read more on cost function here

brainly.com/question/2292799

#SPJ1

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3 years ago
There are 2504 computer science students at a school. Of these, 1876 have taken a course in Java, 999 have taken a course in Lin
Y_Kistochka [10]

Answer:

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Step-by-step explanation:

As per the given data of the question:

Total number of students = 2504

Number of students in Java (J) = 1876

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J∩L = 876

L∩C = 231

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Now according to Venn-diagram as drawn below:

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Number of students who have not taken a course in any of these three subjects

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Hence, the students who have not taken a course in any of these three subjects = 492.

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