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Rasek [7]
1 year ago
12

The student council is hosting a homecoming event for past graduates and current students. The treasurer determines that the eve

nt revenue from the event can be represented by R (z) = 0.05x³75, where x is the number of tickets sold. The cost to put on the event is represented by the function C(z) = 30x + 12,500. Which function describes the funds raised, F(x), as a function of the number of tickets sold? O F(z) F(x) F(x) 0.05³ +30 - 12, 425 F(x) 0.05z³ 30x - 12,425 O = 0.05³ +30 - = 12,575 = 0.05³ 30 - 12,575
Mathematics
1 answer:
xxTIMURxx [149]1 year ago
6 0

The function that describes the fund that was raised is 0.05³ - 30x - 12425

<h3>How to solve for the function</h3>

The revenue is  R (z) = 0.05x³ + 75

the cost = C(z) = 30x + 12,500.

Please note that the equation for revenue missed a sign in the question so I made use of the plus sign

We would have revenue - cost

Hence ( 0.05x³ + 75) - (30x + 12,500)

We would open the bracket

0.05x³ + 75 -30x -12500

We would take the like term to

0.05³ - 30x -12500 + 75

0.05³ - 30x - 12425

The function that describes the fund that was raised is 0.05³ - 30x - 12425

Read more on cost function here

brainly.com/question/2292799

#SPJ1

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Help i made it worth a lot of points
raketka [301]

Answer:

36x^6/y^10

Step-by-step explanation:

First evaluate the parentheses, 6x^3 x 6x^3 = 36x^6

y^5 x y^5 = y^10 ; remember m^k x m^r = m^k+r

final answer should be 36x^6/y^10

hope this helps :')

4 0
2 years ago
Read 2 more answers
Find the exact value of cos theta​, given that sin thetaequalsStartFraction 15 Over 17 EndFraction and theta is in quadrant II.
vova2212 [387]

Answer:

cos \theta = -\frac{8}{17}

Step-by-step explanation:

For this case we know that:

sin \theta = \frac{15}{17}

And we want to find the value for cos \theta, so then we can use the following basic identity:

cos^2 \theta + sin^2 \theta =1

And if we solve for cos \theta we got:

cos^2 \theta = 1- sin^2 \theta

cos \theta =\pm \sqrt{1-sin^2 \theta}

And if we replace the value given we got:

cos \theta =\pm \sqrt{1- (\frac{15}{17})^2}=\sqrt{\frac{64}{289}}=\frac{\sqrt{64}}{\sqrt{289}}=\frac{8}{17}

For our case we know that the angle is on the II quadrant, and on this quadrant we know that the sine is positive but the cosine is negative so then the correct answer for this case would be:

cos \theta = -\frac{8}{17}

5 0
3 years ago
Prove that the conjecture is false by providing a counter example.
Bas_tet [7]

Answer:

Any negative number would be a counterexample.

Step-by-step explanation:

Since negative numbers get smaller as you multiply them by a larger number, this would prove this conjecture false.

6 0
3 years ago
What is the area of a regular hexagon if a side is 30
sergij07 [2.7K]
<h3>Answer:</h3>

1350\sqrt{3} square units (approximately 2338.26859)

<h3>Step-by-step explanation:</h3>

The formula for finding the area of a regular hexagon when you know its side length is A=\frac{3\sqrt{3}*s^2}{2}, where A is the area and s is the side length.

  1. Substitute in the side length. A=\frac{3\sqrt{3}*30^2}{2}
  2. Simplify the exponent. A=\frac{3\sqrt{3}*900}{2}
  3. Multiply. A=\frac{2700\sqrt{3}}{2}
  4. Divide. A=1350\sqrt{3}

1350\sqrt{3} is as simple as the solution can get without estimating, but you can estimate with a calculator to find that it is approximately 2338.26859.

4 0
3 years ago
Does anyone understand atleast one of them
pickupchik [31]

Answer:

Look in explanation.

Step-by-step explanation:

1. 76543^{-4} is the same as \frac{1}{76543^{4} } because since there is a negative exponent, you would want to flip the reciprocal and change the negative to positive.

The rest are very similar to this.

7 0
3 years ago
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