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Komok [63]
3 years ago
9

A. provide the result when the algorithm is run on the array [9,8,7,6,5,4,3,2,1,0].

Mathematics
1 answer:
ira [324]3 years ago
3 0
The answer is B hope this helped
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What are the factors in 6x(x+3)?
VladimirAG [237]

Answer:

The factors are 0 and -3

Step-by-step explanation:

In order to find the factors of this equation, you would have to set each term 6x and (x + 3), equal to 0 separately.

6x = 0

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x + 3 = 0

x = -3

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3 years ago
5 ( x + 7 ) +2 ( y - 1 ) when x=7 and y=2
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Answer:

Step-by-step explanation:

5(x+7) + 2(y-1)

here x=7 and y=2

so 5(7+7)+2(2-1)= 5*14+ 2*1

70+2=72

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Please can someone prove this equation
zubka84 [21]

Answer:

see explanation

Step-by-step explanation:

Using the trigonometric identity

sin²x + cos²x = 1

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6 0
3 years ago
Evaluate the following double integral: xy dA D where the region D is the triangular region whose vertices are (0, 0), (0, 3), (
natulia [17]

Answer:

I= 84

Step-by-step explanation:

for

I=\int\limits^{}_{} \int\limits^{}_D {x*y}  \, dA =  \int\limits^{}_{} \int\limits^{}_D {x*y}  \, dx*dy

since D is the rectangle such that 0<x<3 , 0<y<3

I=\int\limits^{}_{} \int\limits^{}_D {x*y}  \, dA =  \int\limits^{3}_{0} \int\limits^{3}_{0} {x*y}  \, dx*dy =  \int\limits^{3}_{0} {x}  \, dx\int\limits^{3}_{0} {y}  \, dy  = x^{2} /2*y^{2} /2 =  (3^{2} /2 - 0^{2} /2)* (3^{2} /2 - 0^{2} /2) = 3^{4} /4 = 81/4

4 0
3 years ago
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