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Andrews [41]
3 years ago
11

Find the output when the input x is 7

Mathematics
1 answer:
Anvisha [2.4K]3 years ago
7 0
Not enough information
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How many solutions does the system have?<br> y = x + 1 <br> y = 2x - 5<br><br> Please Help
olga55 [171]

Answer:

One solution: x=6, y=7. (6, 7).

Step-by-step explanation:

y=x+1

y=2x-5

-----------

x+1=2x-5

1=2x-x-5

x-5=1

x=1+5

x=6

y=6+1=7

8 0
3 years ago
A) One of the roots of the equation 10x^2−33x+c=0 is 5.3. Find the other root and the coefficient c.
Aleks [24]

Answer:

a) The other root is -2

   The coefficient c = -106

b) q = 35

c) c = -8.75

Step-by-step explanation:

* Lets study the general form of the quadratic equation

* ax² + bx + c = 0

- Their roots are x1 and and x2

- The sum of them = -b/a ⇒ x1 + x2 = -b/a

- The product of them = c/a ⇒ (x1)(x2) = c/a

a) * Assume that the roots of the equation 10x² - 33x + c = 0

     are m and n

∵ m + n = -b/a

∵ a = 10 and b = -33

∴ m + n = -(-33)/10 = 3.3

∵ m = 5.3

∴ 5.3 + n = 3.3 ⇒ n = 3.3 - 5.5 = -2

∴ n = -2

* The other root is -2

∵ m × n = c/a

∵ m = 5.3 , n = -2 , a = 10

∴ (5.3)(-2) = c/10

∴ -10.6 = c/10 ⇒ Multiply both sides by 10

∴ c = -106

* The coefficient c = -106

b) * Assume that the roots of the equation x² - 12x + q = 0

     are m and n

∵ The difference between the roots is 2

∴ m - n = 2 ⇒ (1)

∵ From the equation m + n = -b/a

∵ a = 1 , b = -12

∴ m + n = -(-12)/1 = 12

∴ m + n = 12 ⇒ (2)

* Lets solve the two equation

- Add the two equation to eliminate n

∴ 2m = 14 ⇒ divide both sides by 2

∴ m = 7

* Substitute the value of m in (1) or (2)

∴ 7 - n = 2 ⇒ 7 - 2 = n ⇒ 5 = n

∴ n = 5

∵ mn = c/a

∵ c = q , a = 1

∴ mn = q/1 = q

∴ q = 7 × 5 = 35

* q = 35

c) * Assume that the roots of the equation x² + x + c = 0

     are m and n

∵ The difference between the roots is 6

∴ m - n = 6 ⇒ (1)

∵ From the equation m + n = -b/a

∵ a = 1 , b = 1

∴ m + n = -(1)/1 = -1

∴ m + n = -1 ⇒ (2)

* Lets solve the two equation

- Add the two equation to eliminate n

∴ 2m = 5 ⇒ divide both sides by 2

∴ m = 2.5

* Substitute the value of m in (1) or (2)

∴ 2.5 + n = -1 ⇒ n = -1 - 2.5 = -3.5

∴ n = -3.5

∵ mn = c/a

∵ c = c , a = 1

∴ mn = c/1 = c

∴ c = 2.5 × (-3.5) = -8.75

* c = -8.75

6 0
3 years ago
Can someone help me find the theta and radius please?
IrinaK [193]

Answer:

There is videos online

Step-by-step explanation:

3 0
3 years ago
Find value of P and Q
ch4aika [34]

Answer:

P= 6 \frac{1}{7}\\\\Q = 4 \frac{2}{7}

Step-by-step Explanation

\frac{5 + 3 \sqrt{2} }{5 - 3 \sqrt{2} }  = P+Q\sqrt 2 \\  \\  \frac{(5 + 3 \sqrt{2}) }{(5 - 3 \sqrt{2}) }  \times  \frac{(5 + 3 \sqrt{2}) }{(5   +  3 \sqrt{2} )} = P+Q\sqrt 2 \\  \\  \frac{ {(5 + 3 \sqrt{2} )}^{2} }{ {(5)}^{2}  - (3 \sqrt{2})^{2}  }  = P+Q\sqrt 2 \\  \\ \frac{ {5}^{2} +  {(3 \sqrt{2} )^{2}  + 2.5.3 \sqrt{2} } }{25 - 9 \times 2} = P+Q\sqrt 2 \\  \\\frac{ 25 + 18  + 30 \sqrt{2}  }{25 - 18} = P+Q\sqrt 2 \\  \\\frac{ 43  + 30 \sqrt{2}  }{7} = P+Q\sqrt 2 \\  \\ \frac{43}{7}  +  \frac{30 }{7} \sqrt{2}  = P+Q\sqrt 2 \\  \\ equating \: like \: terms \: on \: both \: sides \\  \\ P =  \frac{43}{7}   \\  \\ \huge \red { \boxed{ P= 6 \frac{1}{7}}}  \\  \\ Q =  \frac{30}{7}  \\  \\ \huge  \orange { \boxed{ Q = 4 \frac{2}{7} }}

4 0
3 years ago
Which is the equation of a line that is perpendicular to the line represented represented by y = 3/4x - 1/2 ?
expeople1 [14]
It will be
.. y = -4/3x +c . . . . . for some value of c

_____
The slope of the perpendicular line will be the negative reciprocal of the slope of the given line, which is 3/4.
6 0
4 years ago
Read 2 more answers
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