Use distance formula d=sqrt root (y2-y1)^2+(x2-x1)^2. So (-3, 4) and (1, 7). D= sqrt root ( 7-4)^2+(-3+1)^2. So now solve d= sqrt (3)^2+(-2)^2. Now d= sqrt 9+4. D= sqrt 13 or 3.60555

We will use trigonometric identities to solve this. I will use θ (theta) for the angle.
First of all, we know that cotθ = 1/tanθ. This is a trigonometric identity.
We can replace cotθ in the expression with 1/tanθ.

Simplify: 1/tanθ * tanθ = tanθ/tanθ = 1
So now, we have:

Next, we also know that secθ = 1/cosθ. This is another trigonometric identity.
We can replace secθ with 1/cosθ in our expression.

Simplify:

Our third trigonometric identity that we will use is tanθ = sinθ/cosθ.
We can replace sinθ/cosθ with tanθ.
Now we have as our final answer:

Hope this helps!
X-6 = 15 / (-5)
x-6 = -3
x = -3+6
x = 3
Answer:
y=2x+3 and y=-2x-3
Step-by-step explanation:
First situation:
2x-y=3
making y subject
y=2x+3
Second situation:
2x+y=-3
making y subject
y=-2x-3